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Weirs design problems

I am designing a sewer network with several weirs and outfalls. For modelling the weir I am using a control structure (inline weir) in the rainwater outlet and a orifice control structure in the waste water outlet.

The obtained results seems to be wrong because of the inline weir. The Manhole A420 overflows although the rainwater outlet is only at 32% of its capacity.

The weir height is 10cm, so it can't be causing such overflow. The result of the same network without the weir is:

I need help with this design.

Thanks in advance.

Parents
  • I recommend setting the calculation option Active Numerical Solver to Explicit (SWMM Solvers).

    I don't see what you described when using that solver.

     

    Regards,

    Craig Calvin

    Bentley Technical Support

  • I have already observed this solution, and it works. But the problem is that I need to use HEC-22 Energy headloss method, and it is not supported by SWMM solvers.
  • Here are some suggestions for an improved solution using the Implicit solver.

    • Remove the control on "Waste water conduit". This control is redundant because the orifice diameter in the control is the same as the pipe diameter.
    • Remove the control on conduit "Rainwater Outlet".
    • Create a weir by completing the following:

    Split conduit "Rainwater Outlet" with a transition

    Before:

    After:

    Transition Properties:

      

    Conduit/Weir Properties:

    1. Remove headloss due to the conduits' bend angle at the transition.

    Set the field "Has User Defined Bend Angle?" to True

    Set the field "Bend Angle (User Defined)" to 0 degrees.

    2. Set the conduit upstream of the transition to have section type Irregular Closed Section

    3. For this example, I calculated the Chord Length for incremental elevations to create the cross section. Copy the following Elevation and Chord Length values (calculated in Excel) and paste them into the Depth Width Curve's Elevation and Width fields.

    Invert Elevation = 1739.74 m

    Weir Height = 0.1 m

    Radius = 0.75 m

     

    Elevation = Distance from Center + Height                

    Chord Length = 2*SQRT((Radius^2)-(DistanceFromCenter^2))

    Height

    Distance

    from Center

    Elevation

    Chord Length

    0.1

    0.65

    1739.84

    0.7483

    0.15

    0.6

    1739.89

    0.9000

    0.2

    0.55

    1739.94

    1.0198

    0.25

    0.5

    1739.99

    1.1180

    0.3

    0.45

    1740.04

    1.2000

    0.35

    0.4

    1740.09

    1.2689

    0.4

    0.35

    1740.14

    1.3266

    0.45

    0.3

    1740.19

    1.3748

    0.5

    0.25

    1740.24

    1.4142

    0.55

    0.2

    1740.29

    1.4457

    0.6

    0.15

    1740.34

    1.4697

    0.65

    0.1

    1740.39

    1.4866

    0.7

    0.05

    1740.44

    1.4967

    0.75

    0

    1740.49

    1.5000

    0.8

    0.05

    1740.54

    1.4967

    0.85

    0.1

    1740.59

    1.4866

    0.9

    0.15

    1740.64

    1.4697

    0.95

    0.2

    1740.69

    1.4457

    1

    0.25

    1740.74

    1.4142

    1.05

    0.3

    1740.79

    1.3748

    1.1

    0.35

    1740.84

    1.3266

    1.15

    0.4

    1740.89

    1.2689

    1.2

    0.45

    1740.94

    1.2000

    1.25

    0.5

    1740.99

    1.1180

    1.3

    0.55

    1741.04

    1.0198

    1.35

    0.6

    1741.09

    0.9000

    1.4

    0.65

    1741.14

    0.7483

    1.45

    0.7

    1741.19

    0.5385

    1.5

    0.75

    1741.24

    0.0000

     

    Regards,

    Craig Calvin

    Bentley Technical Support

    Answer Verified By: Luis Varas Garcia 

  • Here is the profile after making the above changes.

     

    Regards,

    Craig Calvin

    Bentley Technical Support

    Answer Verified By: Luis Varas Garcia 

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