lateral deflection

how can i check whether my column or beam has passed deflection check. for instance if span/180 is check for beam deflection how can i enter? should i use DFF command?
Parents
  • DFF is only to check vertical deflection for beams. For columns, you need to check the node displacements. Lateral deflection of beam needs to be checked manually if there are no intermediate nodes or provide node at middle and check node displacement.
  • Actually, deflection checking is based on the resultant Beam Relative Displacement values, so the use of DFF will correctly evaluate lateral deflections in addition to vertical deflections.  I am jumping into a class right now, but I will post an example after I get out.

    Cheers,

    Chris



  • Here is a simple model to demonstrate that deflection checking is basing its result on the resultant deflection.

    STAAD SPACE
    START JOB INFORMATION
    ENGINEER DATE 22-Dec-09
    END JOB INFORMATION
    INPUT WIDTH 79
    UNIT FEET KIP
    JOINT COORDINATES
    1 0 0 0; 2 30 0 0;
    MEMBER INCIDENCES
    1 1 2;
    DEFINE MATERIAL START
    ISOTROPIC STEEL
    E 4.176e+006
    POISSON 0.3
    DENSITY 0.489024
    ALPHA 6e-006
    DAMP 0.03
    END DEFINE MATERIAL
    MEMBER PROPERTY AMERICAN
    1 TABLE ST W21X48
    CONSTANTS
    MATERIAL STEEL ALL
    SUPPORTS
    1 FIXED
    2 FIXED BUT FX
    LOAD 1 LOADTYPE None TITLE LOAD CASE 1
    MEMBER LOAD
    1 CON Z 6 15
    UNIT INCHES KIP
    1 CON Y -10 180
    UNIT FEET KIP
    PERFORM ANALYSIS
    UNIT INCHES KIP
    PARAMETER 1
    CODE AISC UNIFIED
    FYLD 50 ALL
    DFF 400 ALL
    CHECK CODE ALL
    FINISH 

    The output file shows a dff value of 276.  The ratio of DFF/dff = 400/276 = 1.449 (the controlling ratio).

    The span of the beam is 360 inches.  360/276 = 1.304 inches.

    Check the Beam Relative Displacement Detail table, and note that the Resultant displacement at midspan is 1.302 inches.

    So to summarize, thedff value is being calculated based on the Resultant displacement, and the deflection check will work for lateral deflections as well as for vertical deflections.

    Cheers,

    Chris 

     

     



Reply
  • Here is a simple model to demonstrate that deflection checking is basing its result on the resultant deflection.

    STAAD SPACE
    START JOB INFORMATION
    ENGINEER DATE 22-Dec-09
    END JOB INFORMATION
    INPUT WIDTH 79
    UNIT FEET KIP
    JOINT COORDINATES
    1 0 0 0; 2 30 0 0;
    MEMBER INCIDENCES
    1 1 2;
    DEFINE MATERIAL START
    ISOTROPIC STEEL
    E 4.176e+006
    POISSON 0.3
    DENSITY 0.489024
    ALPHA 6e-006
    DAMP 0.03
    END DEFINE MATERIAL
    MEMBER PROPERTY AMERICAN
    1 TABLE ST W21X48
    CONSTANTS
    MATERIAL STEEL ALL
    SUPPORTS
    1 FIXED
    2 FIXED BUT FX
    LOAD 1 LOADTYPE None TITLE LOAD CASE 1
    MEMBER LOAD
    1 CON Z 6 15
    UNIT INCHES KIP
    1 CON Y -10 180
    UNIT FEET KIP
    PERFORM ANALYSIS
    UNIT INCHES KIP
    PARAMETER 1
    CODE AISC UNIFIED
    FYLD 50 ALL
    DFF 400 ALL
    CHECK CODE ALL
    FINISH 

    The output file shows a dff value of 276.  The ratio of DFF/dff = 400/276 = 1.449 (the controlling ratio).

    The span of the beam is 360 inches.  360/276 = 1.304 inches.

    Check the Beam Relative Displacement Detail table, and note that the Resultant displacement at midspan is 1.302 inches.

    So to summarize, thedff value is being calculated based on the Resultant displacement, and the deflection check will work for lateral deflections as well as for vertical deflections.

    Cheers,

    Chris 

     

     



Children
  • what is the dff value? and which factors will it govern.
  • The value of dff (lowercase letters) is a deflection result that is calculated by "Deflection Length"/Max Deflection. 

    • "Deflection Length" defaults to member length, so in the case of members that consist of multiple analytical members connected by intermediate nodes, it becomes necessary to define a "Deflection Length" by defining a DJ1 and DJ2 parameter to identify the two ends of the "Deflection Length".  In my example in the previous post, "Deflection Length" = member length = 360 inches.
    • Max Deflection is the maximum resultant deflection found to occur anywhere along the length of the member.  Whether studying a single member or a multi-segment member (using DJ1 and DJ2), the Max Deflection value will be normalized to remove the component of deflection that is attributable to the displacement of the end nodes of the member.  In my example in the previous post, the maximum resultant deflection = 1.304 inches.
    • In my example in the previous post, dff = 276 = 360 inches / 1.304 inches.
    • DFF is the user specifed limiting value of dff.  In my example in the previous post, DFF= 400.
    • For the purpose of a unity check, the ratio is calculated as DFF/dff.   In my example in the previous post, DFF/dff = 400/276 = 1.449

    When a code check is performed, the ratio of DFF/dff is calculated just as many other ratios are calculated for evaluating all of the applicable code clauses.  If the value of DFF/dff is found to be the controlling ratio, then it will be indicated as the controlling condition for that member.  If the value of DFF/dff is NOT found to be the controlling ratio, then STAAD.Pro will indicate something OTHER than deflection as being the controlling condition.  (Note that just because a member doesn't indicate deflection as its controlling condition, it does not necessarily mean that the member passes the deflection check.  It just means that something else had a higher ratio than deflection.)

    I hope this helps.

    Cheers,

    Chris



  • Thank you so much for your response, it really cleared up the air. one thing i wanted to ask is usually we simple compare the deflection with span/(some constant value), cant we just do this. for example i have 20 meter span. i put DFF = 180 so the value becomes 20/180 = 0.111m or 111 mm. if deflection exceeds this value the rafter or column fails?
  • It's always our pleasure to help.

    Yes, the value of DFF is your (some constant value).  So in that regard, STAAD.Pro works exactly the way you are asking.

    On the other hand, if you asking for the ability to perform a deflection check without concurrently performing a stress/strength check, that is challenging.  Before I start down that path, I'll let you clarify your intent.

    Cheers,

    Chris



  • Here is my Std File... i cant upload it as there is some error coming at your end. I have given DFF as 180 and have provided Dji and Dj2 for beams accordingly. in my opinion the total length is 19m of beam so max deflection becomes 19/180 = 111mm so any part of beam showing deflection more than that should fail. But there is no deflection exceeding 80mm still all beams are failing with ratio 9. Could you care to explain me where and what i am doing incorrect? STAAD PLANE START JOB INFORMATION ENGINEER NAME ROHAIL ENGINEER DATE 17-MAR-09 END JOB INFORMATION INPUT WIDTH 79 UNIT METER KN JOINT COORDINATES 1 0 0 0; 21 19.2 0 0; 26 19.2 15.64 0; 100 0 12.2 0; 101 0.55 12.2 0; 102 18.65 12.2 0; 103 19.2 12.2 0; 122 0 15.64 0; 130 3.6 16 0; 133 15.6 16 0; 134 9.6 16.6 0; MEMBER INCIDENCES 1 1 100; 2 100 122; 5 21 103; 6 103 26; 7 122 130; 9 26 133; 50 100 101; 51 102 103; 52 130 134; 53 133 134; * MATERIAL PROPERTY UNIT MMS KIP DEFINE MATERIAL START ISOTROPIC STEEL E 44.9499 POISSON 0.3 DENSITY 1.7269e-008 ALPHA 6.5e-006 DAMP 0.03 END DEFINE MATERIAL *MEMBER SIZES MEMBER PROPERTY AMERICAN * COLUMNS 1 5 TAPERED 532 8 900 350 16 2 6 TAPERED 900 8 900 250 10 * RAFTERS 7 9 TAPERED 900 8 600 230 10 52 53 TAPERED 600 5 700 210 8 * BRACKET 50 51 TAPERED 500 8 500 200 10 CONSTANTS MATERIAL STEEL ALL SUPPORTS 1 21 FIXED * MEMBER OFFSETS UNIT MMS KN MEMBER OFFSET 7 9 START LOCAL 450 0 0 2 6 END LOCAL -450 0 0 ** BAY SPACING = 7.838m ** WIND SPEED = 200KPH ** PRESSURE, P = Ce x Cq x Qs x Iw ** PRESSURE, P = 1.40 x 0.70 x 40.10 x 1.0 ** = 1.87 KN/m2 * PRIMARY LOADS UNIT METER KN DEFINE UBC LOAD ZONE 0.2 I 1 RWX 4.5 RWZ 4.5 STYP 4 CT 0.035 NA 1 NV 1 SELFWEIGHT 1 MEMBER WEIGHT 1 2 5 7 9 52 53 UNI -1.69 LOAD 1 S-X UBC LOAD X 1 PERFORM ANALYSIS CHANGE LOAD 2 S-Z UBC LOAD Z 1 PERFORM ANALYSIS CHANGE LOAD 3 LOADTYPE Dead TITLE DL SELFWEIGHT Y -1 MEMBER LOAD * ROOF DEAD LOAD = 0.215 KN/m2 * 7.838m = 1.69KN/m 7 9 52 53 UNI GY -1.69 * WALL DEAD LOAD = 0.095 KN/m2 * 7.838m = 0.74KN/m 1 2 5 6 UNI GY -0.74 * INSULATION = 20 Kg/m2 * 0.050m * 7.838m * 9.81/1000 = 0.08 KN/m 1 2 5 TO 7 9 52 53 UNI GY -0.08 LOAD 4 LOADTYPE Live TITLE LL MEMBER LOAD * LIVE LOAD = 0.57 KN/m2 * 7.838m = 4.5 KN/m 7 9 52 53 UNI GY -4.5 LOAD 5 LOADTYPE Wind TITLE WIND LOAD MEMBER LOAD * WIND PRESSURE = 1.87 KN/m2 * 1.87 KN/m2 X 0.70 X 7.838 = 14.69 KN/m 1 2 UNI GX -14.69 7 9 52 53 UNI GY 14.69 9 53 UNI GY 14.69 5 6 UNI GX 14.69 ************************************** * 5-ton crane -24m span (CRANE A) LOAD 6 CR-A-V-1&H-1 JOINT LOAD 101 FX 34.6 FY -311 102 FX 34.6 FY -82 LOAD 7 CR-A-V-1&H-2 JOINT LOAD 101 FX -34.6 FY -311 102 FX -34.6 FY -82 LOAD 8 CR-A-V-2&H-1 JOINT LOAD 101 FX 34.6 FY -82 102 FX 34.6 FY -311 LOAD 9 CR-A-V-2&H-2 JOINT LOAD 101 FX -34.6 FY -82 102 FX -34.6 FY -311 ************************************** * LOADING COMBINATIONS LOAD COMB 46 DL + EL+X 1 0.71 3 0.9 LOAD COMB 47 DL + EL-X 1 -0.71 3 0.9 LOAD COMB 48 DL + EL+Z 2 0.71 3 0.9 LOAD COMB 49 DL + EL-Z 2 -0.71 3 0.9 LOAD COMB 50 DL + LL 3 0.71 4 0.9 LOAD COMB 51 DL + WIND LOAD 3 0.71 5 0.9 LOAD COMB 52 DL + 0.75 LL + 0.75 WIND LOAD 3 0.75 4 0.75 5 0.75 LOAD COMB 53 DL + 0.75 LL + 0.71 EL-X 3 0.75 4 0.75 1 0.71 LOAD COMB 54 DL + 0.75 LL + 0.71 EL-Z 3 0.75 4 0.75 2 0.71 ** DL + Crane LOAD COMB 55 DL+CRANE 3 1.0 6 1.0 LOAD COMB 56 DL+CRANE 3 1.0 7 1.0 LOAD COMB 57 DL+CRANE 3 1.0 8 1.0 LOAD COMB 58 DL+CRANE 3 1.0 9 1.0 **DL+CRANE+WIND-LOAD COMBINATIONS LOAD COMB 59 DL+ 0.75 CRANE+ 0.75 WIND LOAD 3 1.0 6 0.75 5 0.75 LOAD COMB 60 DL+ 0.75 CRANE+ 0.75 WIND LOAD 3 1.0 7 0.75 5 0.75 LOAD COMB 61 DL+ 0.75 CRANE+ 0.75 WIND LOAD 3 1.0 8 0.75 5 0.75 LOAD COMB 62 DL+ 0.75 CRANE+ 0.75 WIND LOAD 3 1.0 9 0.75 5 0.75 ************************************** * Analysis ************************************** PERFORM ANALYSIS PRINT ALL LOAD LIST 46 TO 62 *PARAMETERS PARAMETER 1 CODE AISC FYLD 344522 ALL TRACK 2 ALL DFF 180 ALL * COLUMNS KX 1 MEMB 1 2 5 6 KY 1 MEMB 1 2 5 6 KZ 2 MEMB 1 2 5 6 LX 3 MEMB 1 2 5 6 LY 3 MEMB 1 2 5 6 LZ 15.3 MEMB 1 2 5 6 UNB 3 MEMB 1 2 5 6 UNT 3 MEMB 1 2 5 6 * RAFTERS KX 1 MEMB 7 9 52 53 KY 1 MEMB 7 9 52 53 KZ 0.75 MEMB 7 9 52 53 LX 1 MEMB 7 9 52 53 LY 3 MEMB 7 9 52 53 LZ 19.2 MEMB 7 9 52 53 UNB 3 MEMB 7 9 52 53 UNT 1 MEMB 7 9 52 53 ** DEFLECTION CHECK DJ1 122 MEMB 7 9 52 53 DJ2 26 MEMB 7 9 52 53 * BRACKET KX 1 MEMB 50 51 KY 1 MEMB 50 51 KZ 2 MEMB 50 51 LX 0.55 MEMB 50 51 LY 0.55 MEMB 50 51 LZ 0.55 MEMB 50 51 UNB 0.55 MEMB 50 51 UNT 0.55 MEMB 50 51 CHECK CODE ALL STEEL TAKE OFF ALL FINISH