如题，我有一个a.dgn，在a.dgn的file和designmodel上分别写入了xattribute
现在在b.dgn中参考了a.dgn的designmodel。使用以下代码，在b.dgn中无法读取xattribute。
DgnAttachmentP att = ACTIVEMODEL->GetDgnAttachmentsCP()->at(0); DgnFileP dgnFileP = att->GetDgnFileP(); ApplicationSettings appSet = IDgnSettings::GetCurrentSettings().GetFileApplicationSettings(*dgnFileP); //ApplicationSettings appSet = IDgnSettings::GetCurrentSettings().GetModelApplicationSettings(*att); //改成读取model也不行 XAttributeHandlerId xAttHandlerId(100, 1); ElementRefP elRef = appSet.GetElementRef(); XAttributeHandle xah(elRef, xAttHandlerId, 3); if (xah.IsValid())//这里判断无效，无法读取 { char* chars = (char*)xah.PeekData(); }
看起来GetCurrentSettings只对当前dgn有效？
请问以上需求该如何实现？
试试调用一下DgnFile的LoadDgnFile和FillDictionaryModel
两个方法均返回success，但结果还是一样xah.IsValid()返回false
我用如下代码测试完全没有问题，测试步骤在被参考的文件中函数参数传递0完成添加属性的操作，然后在主文件中参数传递1能够读取到添加的属性：
void applicationSettingTest(int condition) { /*DgnAttachmentP dgnAtta = *ACTIVEMODEL->GetDgnAttachmentsP()->begin(); ApplicationSettings appSet = IDgnSettings::GetCurrentSettings().GetModelApplicationSettings(*dgnAtta);*/ ApplicationSettings appSet = IDgnSettings::GetCurrentSettings().GetModelApplicationSettings(*ACTIVEMODEL); XAttributeHandlerId handlerId(900, 800); //MajorId, MinorId UInt32 xattrId = 1; char *appData = "My Application Data"; switch (condition) { case 0: //--Create ApplicationSetting appSet.SaveSetting(handlerId, xattrId, appData, (UInt32)strlen(appData)); break; case 1: //--Display ApplicationSetting { ElementRefP elRef = appSet.GetElementRef(); ElementId elId = elementRef_getElemID(elRef); printf("%d\n", elId); XAttributeHandle xah(elRef, handlerId, xattrId); if (xah.IsValid()) { printf("%s\n", xah.PeekData()); } break; } case 2: //--Remove ApplicationSetting { ElementRefP elRef = appSet.GetElementRef(); XAttributeHandle xah(elRef, handlerId, xattrId); if (xah.IsValid()) { ITxnManager::GetManager().GetCurrentTxn().DeleteXAttribute(xah); } break; } } }
Answer Verified By: Chao Cheng
在主文件中测试获取属性时，要注释掉第5行，把3，4行的注释去掉。
感谢，代码没问题，最终发现是本地的dgn有问题。