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<?xml-stylesheet type="text/xsl" href="https://communities.bentley.com/cfs-file/__key/system/syndication/rss.xsl" media="screen"?><rss version="2.0" xmlns:dc="http://purl.org/dc/elements/1.1/"><channel><title>Derek Larsen's Activities</title><link>https://communities.bentley.com/members/0db53c36_2d00_c79f_2d00_43e8_2d00_b7ca_2d00_90bfc7f88f80</link><description>Derek Larsen's recent activity</description><dc:language>en-US</dc:language><generator>Telligent Community 12</generator><item><title>Code Minimum Steel in Ram Concept for PT Slab</title><link>https://communities.bentley.com/products/ram-staad/f/ram-staad-forum/236830/code-minimum-steel-in-ram-concept-for-pt-slab</link><pubDate>Tue, 11 Oct 2022 18:21:11 GMT</pubDate><guid isPermaLink="false">6dad98f5-dbc9-4c4d-a9ba-e9da8dc6aa8e:81b74f7a-72ac-4643-847f-221c7063263b</guid><dc:creator>Derek Larsen</dc:creator><description>&lt;p&gt;I am trying to understand how Ram Concept applies the code section ACI 318-14 section 8.6.2.3, which simply calls for 0.00075 x Acf.&lt;/p&gt;
&lt;p&gt;Here is the cross section in question from the &amp;quot;Audit Cross Section&amp;quot; tool.&amp;nbsp; Acf in this direction is 3205 inches squared, which I take no issue with.&amp;nbsp; 0.00075 x 3205 inches square = 2.41 inches squared = (8) #5&amp;#39;s&lt;/p&gt;
&lt;p&gt;&lt;img alt=" " src="/resized-image/__size/640x480/__key/communityserver-discussions-components-files/5932/2538.Capture1.PNG" /&gt;&lt;/p&gt;
&lt;p&gt;&lt;/p&gt;
&lt;p&gt;The program actually picks out (13) #5 bars, so I tried to figure out where that comes from by the Audit Cross section tool:&lt;/p&gt;
&lt;p&gt;&lt;img alt=" " src="/resized-image/__size/640x480/__key/communityserver-discussions-components-files/5932/0336.Capture2.PNG" /&gt;&lt;/p&gt;
&lt;p&gt;This shows a number called Acf(Parallel) and they call it span section area.&amp;nbsp; I have no idea what this area is or where it is in the ACI code.&amp;nbsp; This is a much larger area than the cross section in the longitudinal direction.&amp;nbsp; Could you clarify where this area is coming from?&lt;/p&gt;
&lt;p&gt;&lt;br /&gt;Thanks,&lt;/p&gt;&lt;div style="clear:both;"&gt;&lt;/div&gt;</description></item><item><title>Ram Structural System  with Ram Concept - LLR Parameters</title><link>https://communities.bentley.com/products/ram-staad/f/ram-staad-forum/227598/ram-structural-system-with-ram-concept---llr-parameters</link><pubDate>Fri, 25 Mar 2022 23:07:49 GMT</pubDate><guid isPermaLink="false">6dad98f5-dbc9-4c4d-a9ba-e9da8dc6aa8e:02c7bbe6-45f8-48c7-9103-8fcd7a957d03</guid><dc:creator>Derek Larsen</dc:creator><description>&lt;p&gt;So I am entering the LLR Parameters manually in a 3 over 1 Podium building and am trying to get the Live Load reduction to work.&amp;nbsp; On my job, I have (3) levels, so I thought if I input an area for one level, and then input the total number of levels, that the program would then do the live load reduction based on 3 times the input area.&amp;nbsp; I just went through the latitude design strips, and input the area of each design strips (taken directly from a plan where &amp;quot;Visible Objects:LLR Parameters&amp;quot; is turned on).&amp;nbsp; I input that area in both the Trib Area and Influence Area values on the LLR tab of the design strip settings dialog.&amp;nbsp; I then input the number of levels as 3.&amp;nbsp; The &amp;#39;LLR Levels&amp;#39; didn&amp;#39;t appear to make any changes to how the program calculated the LLR.&amp;nbsp;&amp;nbsp;&amp;nbsp; &amp;nbsp; &amp;nbsp;&lt;/p&gt;
&lt;p&gt;As an example, 1 bay of a continuous design strip that I have has LLR Parameters area of 681 sf.&amp;nbsp; It is roughly 28&amp;#39;-0&amp;quot; long by 24&amp;#39;-0&amp;quot; wide so that area appears correct.&amp;nbsp; I have the LLR Calculations set to the 2018 IBC.&amp;nbsp; I went through and input manually that the &amp;quot;LLR Levels&amp;quot; = 3 and the&amp;nbsp;Trib Area&amp;nbsp;= 681 sf, and the program calculates a 17.5% reduction.&amp;nbsp; This 17.5% reduction is what you would calculate by IBC 2018 Equation 16-23 for a&amp;nbsp;681 square foot&amp;nbsp;area and a Kll = 1.0 for a two way slab.&amp;nbsp;&lt;/p&gt;
&lt;p&gt;I thought the whole reason to have the LLR Levels input was so I wouldn&amp;#39;t have to calculate by hand the area is 3 times the area that I input (when you have dozens of bays in two directions, and you are inputting the areas manually, adding a calculation to it would be even more cumbersome).&amp;nbsp; So what is the point of the LLR Levels line?&amp;nbsp; What am I doing wrong?&lt;/p&gt;
&lt;p&gt;&amp;nbsp; &lt;img alt=" " src="/resized-image/__size/320x240/__key/communityserver-discussions-components-files/5932/Ram-Concept-LLR.PNG" /&gt;&amp;nbsp; &amp;nbsp; &amp;nbsp; &amp;nbsp;&amp;nbsp;&lt;/p&gt;&lt;div style="clear:both;"&gt;&lt;/div&gt;</description></item><item><title>Problem with Ram Concept Version 3 - Mat Foundations</title><link>https://communities.bentley.com/products/ram-staad/f/ram-staad-forum/225259/problem-with-ram-concept-version-3---mat-foundations</link><pubDate>Mon, 31 Jan 2022 23:43:25 GMT</pubDate><guid isPermaLink="false">6dad98f5-dbc9-4c4d-a9ba-e9da8dc6aa8e:8aaf4f60-2a88-4823-b580-7860dba7a36d</guid><dc:creator>Derek Larsen</dc:creator><description>&lt;p&gt;A co-worker was using Ram Concept Version 3 to design some Mat Foundations, and it wasn&amp;#39;t reporting any bearing pressures for the purely gravity load load cases (D+S, D+L, D, etc).&amp;nbsp; So I opened one of my old files in Ram Version 2, got the bearing pressures for those gravity load cases.&amp;nbsp; Then I upgraded to Version 3, opened the same file, ran it, and did not calculate any bearing pressures for the gravity load cases.&amp;nbsp; Just curious if this is a bug or if there is some new settings we are not aware of.&lt;/p&gt;&lt;div style="clear:both;"&gt;&lt;/div&gt;</description></item><item><title>Ask A Question I</title><link>https://communities.bentley.com/achievements/460ac7df-7ccc-4c42-a204-9e05eef3be09</link><pubDate>Tue, 18 Jan 2022 02:33:25 GMT</pubDate><guid isPermaLink="false">6dad98f5-dbc9-4c4d-a9ba-e9da8dc6aa8e:0754f197-b243-444a-985a-b711b99256b4</guid><dc:creator /><description>Ask a question in a forum.</description></item><item><title>Does Ram Structural system allow you to adjust the in-plane base fixity of shear walls when they are tilt-ups without holdowns?</title><link>https://communities.bentley.com/products/ram-staad/f/ram-staad-forum/224674/does-ram-structural-system-allow-you-to-adjust-the-in-plane-base-fixity-of-shear-walls-when-they-are-tilt-ups-without-holdowns</link><pubDate>Tue, 18 Jan 2022 02:32:56 GMT</pubDate><guid isPermaLink="false">6dad98f5-dbc9-4c4d-a9ba-e9da8dc6aa8e:67bba613-d747-4f4c-923c-d39e0c727ad4</guid><dc:creator>Derek Larsen</dc:creator><description>&lt;p&gt;For modeling tilt-up walls in Ram Structural system, we were curious as to the proper base fixity when holdowns are not used on the wall.&amp;nbsp; It seems that a fully fixed in-plane stiffness would not be appropriate, but we were unable to find any way to modify its in plane stiffness.&amp;nbsp;&amp;nbsp;&lt;/p&gt;&lt;div style="clear:both;"&gt;&lt;/div&gt;</description></item></channel></rss>