vivekshine's Activities

Maximum Utility ratio for each section in STAAD

Vivekanandan K — Fri, 24 Mar 2023 05:50:52 GMT

Is there any option to see Maximum Utility ratio for each section in STAAD. In v8i version we can take the Maximum Utility ratio table using SQL query. but in CE version it is not available. Is there any option to see this format table.

Existing RCC wall analysis in STAAD

vivekshine — Tue, 09 May 2017 10:03:09 GMT

I have to analyse an existing RCC wall. I have the wall dimension and rebar details.

How to model RCC in STAAD. I can able to model only concrete as shear wall(surface). But could not add any steel reinforcement in to the wall. Can anyone tell me the procedure to analyse such RCC wall to find the load bearing capacity of the wall.

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Mon, 27 Sep 2021 14:15:56 GMT

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UNT /UNB is based on flange or bracing

vivekshine — Mon, 27 Sep 2021 14:15:54 GMT

In the attached model UNB/UNT values for intermediate secondary members(Z direction) as 1m and Primary members (X-Direction) as 5 m(Physical beam length).

Taking UNT/UNB for Primary members (UC305X305X97) as 5m is correct or do we need to consider 1m as this beams are tied at 1m interval?

IS UNT UMN Ly is same in most Cases?

STAAD SPACE
START JOB INFORMATION
ENGINEER DATE 02-Sep-21
END JOB INFORMATION
INPUT WIDTH 79
UNIT METER KN
JOINT COORDINATES
1 0 0 0; 2 1 0 0; 3 2 0 0; 4 3 0 0; 5 4 0 0; 6 5 0 0; 7 0 0 1; 8 1 0 1;
9 2 0 1; 10 3 0 1; 11 4 0 1; 12 5 0 1; 13 0 0 2; 14 1 0 2; 15 2 0 2; 16 3 0 2;
17 4 0 2; 18 5 0 2; 19 0 0 3; 20 1 0 3; 21 2 0 3; 22 3 0 3; 23 4 0 3; 24 5 0 3;
25 0 0 4; 26 1 0 4; 27 2 0 4; 28 3 0 4; 29 4 0 4; 30 5 0 4;
MEMBER INCIDENCES
1 1 2; 2 2 3; 3 3 4; 4 4 5; 5 5 6; 6 1 7; 7 2 8; 8 3 9; 9 4 10; 10 5 11;
11 6 12; 12 7 8; 13 8 9; 14 9 10; 15 10 11; 16 11 12; 17 7 13; 18 8 14;
19 9 15; 20 10 16; 21 11 17; 22 12 18; 23 13 14; 24 14 15; 25 15 16; 26 16 17;
27 17 18; 28 13 19; 29 14 20; 30 15 21; 31 16 22; 32 17 23; 33 18 24; 34 19 20;
35 20 21; 36 21 22; 37 22 23; 38 23 24; 39 19 25; 40 20 26; 41 21 27; 42 22 28;
43 23 29; 44 24 30; 45 25 26; 46 26 27; 47 27 28; 48 28 29; 49 29 30;
DEFINE MATERIAL START
ISOTROPIC STEEL
E 2.05e+008
POISSON 0.3
DENSITY 76.8195
ALPHA 1.2e-005
DAMP 0.03
TYPE STEEL
STRENGTH FY 253200 FU 407800 RY 1.5 RT 1.2
END DEFINE MATERIAL
MEMBER PROPERTY BRITISH
1 TO 6 11 TO 17 22 TO 28 33 TO 39 44 TO 49 TABLE ST UC305X305X97
7 TO 10 18 TO 21 29 TO 32 40 TO 43 TABLE ST UB203X133X30
CONSTANTS
MATERIAL STEEL ALL
SUPPORTS
1 6 13 18 25 30 PINNED
LOAD 1 LOADTYPE None TITLE LOAD CASE 1
SELFWEIGHT Y -1
MEMBER LOAD
1 TO 49 UNI GY -30
PERFORM ANALYSIS PRINT ALL
PARAMETER 1
CODE AISC UNIFIED 2010
UNB 5 MEMB 1 TO 5 12 TO 16 23 TO 27 34 TO 38 45 TO 49
UNT 5 MEMB 1 TO 5 12 TO 16 23 TO 27 34 TO 38 45 TO 49
UNB 4 MEMB 6 11 17 22 28 33 39 44
UNT 4 MEMB 6 11 17 22 28 33 39 44
UNB 1 MEMB 7 TO 10 18 TO 21 29 TO 32 40 TO 43
UNT 1 MEMB 7 TO 10 18 TO 21 29 TO 32 40 TO 43
CHECK CODE ALL
FINISH

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Mon, 27 Sep 2021 02:03:10 GMT

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+Fy restraint support

vivekshine — Tue, 29 Sep 2015 05:02:06 GMT

Dear Engineers,

Is it possible to create +Fy restraint support in STAAD?

When I use

FIXED BUT FX FZ MX MY MZ

It restraint in both +Fy and -Fy

My condition is simple rest support. Only +Fy restraint and -Fy is free

Is it possible to create such a support in STAAD?

Modelling with member offset and without- which one is correct

vivekshine — Sat, 16 May 2015 08:31:32 GMT

Generally in STAAD Pro we model by connecting centre to centre nodes. Like this...

But actual will be different from the above. We can use the member offset option to do like real model. But most of us not doing member offset. Is that correct way of modeling? There is a big difference in reaction between with member offset command and without member offset command.

Which way of modeling is correct…!

With member offset and without member offset ...?

Rebar placement in RCC rectangular water Tank

vivekshine — Tue, 16 Dec 2014 07:05:24 GMT

Dear Engineers,

Im detailing RCC rectangular water Tank.

Got the ast and Rebar details.

Could you pls. clarify which way of rebar placement is correct among the below(Section A or B).

i.e in Tank Wall the vertical reinforcement bar will come inside or outside of the horizontal reinforcement bar?

In circular tanks vertical reinforcement will come in side the horizontal reinforcement . In Rectangular tanks ?

STAAD-Unable to apply Wind load for cooling tower(Structure with only plates)

vivekshine — Mon, 12 Mar 2018 17:03:03 GMT

Why Unable to apply Wind load for cooling tower kind of structure. i.e Structure with only plates or surfaces.

Error Shows :

**ERROR NO MEMBERS IN RANGE IN WIND LOAD.

Practically there won't be beams or column members in such a structure.

Is there any other way to apply wind load for this type of structures.

Discussion Starter I

Mon, 12 Mar 2018 09:08:07 GMT

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Temperature load in STAAD (Thermal load of steel )

vivekshine — Tue, 02 Feb 2016 10:40:47 GMT

Dear Engineers,

Im analysing a steel structure where I have to apply thermal load. below are the datas.

Max. Temp 45 deg Celsius
Min.Temp -35 deg Celsius
Site Average maximum temperature : 36°C
Site Average minimum temperature : -22°C

In STAAD we have below 3 things in the input cell. How to calculate this from the above input.

Temperature Change for Axial Elongation

Temperature Differential from Top to Bottom

Temperature Differential from side to side

deflection in z direction

eng_ahmed — Tue, 09 May 2017 08:22:59 GMT

i have side girt c channel in steel building and it is affected with dead load acting on it's weak axis as shown

i want to know the deflection in z direction due to dead load (staad only show deflection in y direction ) ,i add staad file

STAAD SPACE
START JOB INFORMATION
ENGINEER DATE 05-Mar-17
END JOB INFORMATION
INPUT WIDTH 79
UNIT METER KN
JOINT COORDINATES
11 -5 4.2 0; 12 1.5 4.2 0; 13 1.475 12.4 0; 14 -5 12.4 0;
MEMBER INCIDENCES
5 11 12; 6 13 14;
*START GROUP DEFINITION
*JOINT
*END GROUP DEFINITION
DEFINE MATERIAL START
ISOTROPIC STEEL
E 2.05e+008
POISSON 0.3
DENSITY 76.8195
ALPHA 1.2e-005
DAMP 0.03
TYPE STEEL
STRENGTH FY 253200 FU 407800 RY 1.5 RT 1.2
END DEFINE MATERIAL
MEMBER PROPERTY COLDFORMED AMERICAN
6 TABLE ST JWE8X102CS
MEMBER PROPERTY AMERICAN
5 TABLE ST C6X8
CONSTANTS
MATERIAL STEEL ALL
SUPPORTS
11 TO 14 PINNED
LOAD 1 LOADTYPE Dead TITLE DL
SELFWEIGHT Y -1
MEMBER LOAD
*for vertical studs
*for purlins
6 UNI Y -0.14
*for horizontal studs in walls
*for horizontal studs with span 3.5m in walls
5 UNI GZ 0.22
LOAD 2 LOADTYPE Live TITLE LL
MEMBER LOAD
6 UNI Y -1.17
LOAD 3 LOADTYPE Wind TITLE WLZ
MEMBER LOAD
5 UNI Y -0.92
6 UNI Y 1.68
LOAD COMB 4 COMBINATION LOAD CASE 4
1 1.0 2 1.0
LOAD COMB 5 0.6DL+LL
1 0.6 2 1.0
LOAD COMB 6 0.6D+WL
1 0.6 3 1.0
PERFORM ANALYSIS
*spacing for 1 meters
PARAMETER 1
CODE AISI
BEAM 1 MEMB 5
FLX 1 ALL
LT 0.3 ALL
LY 1.9 MEMB 5
LY 3.25 MEMB 6
CHECK CODE MEMB 6
PERFORM ANALYSIS
*spacing for 2 meters
PARAMETER 2
CODE AISC UNIFIED 2005
METHOD ASD
FYLD 248213 MEMB 5
CB 1 MEMB 5
DFF 0.027 MEMB 5
DJ2 14 MEMB 5
DJ1 13 MEMB 5
BEAM 1 MEMB 5
LZ 2.875 MEMB 5
LY 2.875 MEMB 5
UNT 0.3 MEMB 5
CHECK CODE MEMB 5
STEEL MEMBER TAKE OFF LIST 5
PERFORM ANALYSIS
FINISH

Water Tank Design

vivekshine — Fri, 25 Apr 2014 09:10:47 GMT

Dear Engineers,

Im designing Square Steel water tank using STAAD. I have few doubt. pls. clarify if u have could... Thanks in advance.

1) say the size is 3m x 3m x 2m

Hence volume = 18m3

Weight of water =18*1000 = 18000kg

Pressure on bottom of the tank will be 2000kg/m2

How to calculate the pressure on side wall of the tank

2) When there are so many stress result is shown in post-processing . Which stress do we need to consider for design. Is max Absolute ok?

UNT and UNB AISC 2010

Jorge Ochoa León — Wed, 16 Nov 2016 19:56:52 GMT

Hi,

Do I have to use the command UNT either UNB for beams that already have lateral support as show in the picture (selected)?

Thanks!

Problem with DFF command not check in steel design with STAAD Pro SS6 built 20071150 (Latest built)

siwalak khamnurak — Sat, 06 Feb 2016 04:20:34 GMT

Please see STAAD input command below. I try to change DFF parameter in any value (not 0) but the result still show all member pass all code check.

Please verify if I'm wrong...

Best regard.

STAAD SPACE
START JOB INFORMATION
ENGINEER DATE 06-Feb-16
END JOB INFORMATION
INPUT WIDTH 79
UNIT METER KG
JOINT COORDINATES
1 0 5 0; 2 10 5 0; 3 0 4.91 1.7; 4 10 4.91 1.7; 5 0 4.93656 1.19832;
6 10 4.93656 1.19832; 7 0 3.8 0; 8 10 3.8 0; 9 0 4.99207 0.14979;
10 10 4.99207 0.14979; 11 0 4.9511 0.923706; 12 10 4.9511 0.923706;
MEMBER INCIDENCES
1 1 9; 2 2 10; 3 3 4; 4 5 3; 5 6 4; 6 7 5; 7 8 6; 8 9 11; 9 10 12; 10 9 10;
11 11 5; 12 12 6; 13 11 12;
START GROUP DEFINITION
FLOOR
_CP1 3 TO 5 8 TO 13
END GROUP DEFINITION
DEFINE MATERIAL START
ISOTROPIC STEEL
E 2.09042e+010
POISSON 0.3
DENSITY 7833.41
ALPHA 1.2e-005
DAMP 0.03
TYPE STEEL
STRENGTH FY 2.58192e+007 FU 4.1584e+007 RY 1.5 RT 1.2
END DEFINE MATERIAL
MEMBER PROPERTY JAPANESE
1 2 4 5 8 9 11 12 TABLE ST C150X75X9
3 10 13 TABLE ST RHS150X75X2.3
6 7 TABLE ST C100X50X5
CONSTANTS
BETA 180 MEMB 2 5 7 9 12
MATERIAL STEEL ALL
SUPPORTS
1 2 7 8 PINNED
LOAD 1 LOADTYPE None TITLE DL
SELFWEIGHT Y -1
FLOOR LOAD
_CP1 FLOAD -10 GY
LOAD 2 LOADTYPE None TITLE LR
FLOOR LOAD
_CP1 FLOAD -30 GY
LOAD 3 LOADTYPE None TITLE WX
FLOOR LOAD
_CP1 FLOAD 50 GY
LOAD 4 LOADTYPE None TITLE WZ
FLOOR LOAD
_CP1 FLOAD 70 GY
LOAD COMB 101 DL+LR
1 1.0 2 1.0
LOAD COMB 102 DL+0.75[LR+WX]
1 1.0 2 0.75 3 0.75
LOAD COMB 103 DL+0.75[LR+WZ]
1 1.0 2 0.75 4 0.75
LOAD COMB 104 DL+WX
1 1.0 3 1.0
LOAD COMB 105 DL+WZ
1 1.0 4 1.0
LOAD COMB 106 0.6DL+WX
1 0.6 3 1.0
LOAD COMB 107 0.6DL+WZ
1 0.6 4 1.0
PERFORM ANALYSIS
LOAD LIST 101 TO 107
PARAMETER 1
CODE AISC UNIFIED 2005
METHOD ASD
MAIN 1 MEMB 3 10 13
TMAIN 1 MEMB 3 10 13
*LY 5 MEMB 3 10 13
DFF 1000 MEMB 3 10 13
DJ1 9 MEMB 10
DJ2 12 MEMB 10
CHECK CODE ALL
FINISH