BS EN 806 -2006

Does anybody know the equation Hevacomp uses to convert loading units to flow rates based on the BS EN 806-2006 method? Thanks.

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  • Hi Liam

    It is quite a complex procedure. You need to consider that there are two equations. One that works exclusively with the LU of the outlet, the second that works with the peak outlet in a section.

    For LU's larger than 300:

    dim = loading units

    m = (log(9)-log(1.7)) / (log(5000) - log(300))

    c= log(1.7)-m*(log(300)

    flowrate  = exp(m * log(dim) +c)

    For LU's smaller than 300:

    pdim = peak loading units for section

    m = (log(1.7) - log(pdim)/10)) /(log(300)-log(pdim))

    c = log(pdim/10) - m * log (pdim)

    flowrate  = exp(m * log(dim) +c)

    This differs substantially from BS 6700:

    For LU's larger than 2000:

    dim = loading units 

    flow = specified flow rate (if any)

    m = 11.2 + (dim-2000) * 0.0039

    flowrate = flow + m

    For LU's smaller than 2000:

    dim = loading units 

    flow = specified flow rate (if any)

    m = .0.0532 * dim ^ 0.7

    flowrate = flow + m

    For further information on the pipe sizing standards, please consider this document. For more information about the methods considered by BS 6700, please see this document

    Best regards,

    Duncan Brown



Reply
  • Hi Liam

    It is quite a complex procedure. You need to consider that there are two equations. One that works exclusively with the LU of the outlet, the second that works with the peak outlet in a section.

    For LU's larger than 300:

    dim = loading units

    m = (log(9)-log(1.7)) / (log(5000) - log(300))

    c= log(1.7)-m*(log(300)

    flowrate  = exp(m * log(dim) +c)

    For LU's smaller than 300:

    pdim = peak loading units for section

    m = (log(1.7) - log(pdim)/10)) /(log(300)-log(pdim))

    c = log(pdim/10) - m * log (pdim)

    flowrate  = exp(m * log(dim) +c)

    This differs substantially from BS 6700:

    For LU's larger than 2000:

    dim = loading units 

    flow = specified flow rate (if any)

    m = 11.2 + (dim-2000) * 0.0039

    flowrate = flow + m

    For LU's smaller than 2000:

    dim = loading units 

    flow = specified flow rate (if any)

    m = .0.0532 * dim ^ 0.7

    flowrate = flow + m

    For further information on the pipe sizing standards, please consider this document. For more information about the methods considered by BS 6700, please see this document

    Best regards,

    Duncan Brown



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