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<?xml-stylesheet type="text/xsl" href="https://communities.bentley.com/cfs-file/__key/system/syndication/rss.xsl" media="screen"?><rss version="2.0" xmlns:dc="http://purl.org/dc/elements/1.1/" xmlns:slash="http://purl.org/rss/1.0/modules/slash/" xmlns:wfw="http://wellformedweb.org/CommentAPI/"><channel><title>Axisymmetric model conversions</title><link>https://communities.bentley.com/products/geotech-analysis/f/forum/246318/axisymmetric-model-conversions</link><description>Hello, 
 
 Just a quick question about axisymmetric modelling in Plaxis2D: 
 
 1) When inputting data and also reading the outputs in an axisymmetric model in Plaxis, you need to divide the input force and multiply the output forces by 2*pi to account</description><dc:language>en-US</dc:language><generator>Telligent Community 12</generator><item><title>RE: Axisymmetric model conversions</title><link>https://communities.bentley.com/thread/769071?ContentTypeID=1</link><pubDate>Fri, 09 Jun 2023 07:43:08 GMT</pubDate><guid isPermaLink="false">6dad98f5-dbc9-4c4d-a9ba-e9da8dc6aa8e:dabe4b41-4c52-418b-aac7-cf28e04944b3</guid><dc:creator>Dennis Waterman</dc:creator><description>&lt;p&gt;Dear Farbod,&lt;/p&gt;
&lt;p&gt;1) It depends on what PLAXIS version you&amp;#39;re using. We have in the past presented output results for loads as kPa/rad, in which case indeed it would have to be multiplied by 2*pi to get the total force. However, nowadays we present forces also in axisymmetry in kPa/m, which means that to get the total force you would have to multiply it by 2*pi*R.&amp;nbsp; &amp;nbsp;So please check your input and output to see if data is per radian or per meter.&lt;/p&gt;
&lt;p&gt;2) 3) those are correct assumptions.&lt;/p&gt;
&lt;p&gt;With kind regards,&lt;/p&gt;
&lt;p&gt;Dennis Waterman&lt;/p&gt;&lt;div style="clear:both;"&gt;&lt;/div&gt;</description></item><item><title>RE: Axisymmetric model conversions</title><link>https://communities.bentley.com/thread/769068?ContentTypeID=1</link><pubDate>Fri, 09 Jun 2023 07:30:23 GMT</pubDate><guid isPermaLink="false">6dad98f5-dbc9-4c4d-a9ba-e9da8dc6aa8e:e30eca86-af18-4fee-ba91-3c78fe8a4408</guid><dc:creator>Vasileios Basas</dc:creator><description>&lt;p&gt;Hi Farbod,&lt;/p&gt;
&lt;p&gt;1. This depends on the type of input/output you refer to. For example, using a line load on an axisymmetric model is similar to applying a vertical pressure equal to that line load. This means the total load will equal F&lt;sub&gt;tot&lt;/sub&gt; = Q * &amp;pi; * r&lt;sup&gt;2&lt;/sup&gt;. An example is given in Tutorial #1 (Settlement of a circular footing on sand). In Output, only the reaction Forces (Fy) is expressed in the unit of force per radian. Hence, to calculate the total reaction force under a circular footing that is simulated by means of prescribed displacements, the Fy value should be multiplied by 2&amp;pi;. &lt;span style="text-decoration:underline;"&gt;All other output for axisymmetric problems is given per unit width&lt;/span&gt; and not per radian.&lt;br /&gt;2. Correct. However, you need to be aware that in an axisymmetric analysis, x represents the radial coordinate, y represents the axial coordinate and z represents the tangential direction. In this case, &amp;sigma;&lt;sub&gt;xx&lt;/sub&gt; represents the radial stress and &amp;sigma;&lt;sub&gt;zz&lt;/sub&gt; represents the hoop stress.&lt;br /&gt;3. Correct. No conversion is necessary,&lt;/p&gt;&lt;div style="clear:both;"&gt;&lt;/div&gt;</description></item></channel></rss>