Bisector between two 3D lines

Hi Richard,

I think I understand what you are looking for, I could have a look later in the week but I thought I would share a video I did for some facade panels as in example of measuring angels etc. It might give you some clues on how to get it to project onto a common plane regardless of the 3d nature of the lines. 

https://youtu.be/r1LvlHbhfig

Hope that helps a bit.

Thanks

Wayne

Hi Richard

Is this what you are referring to when you say rotated around the Z? Its taking the original curve and flattening it on a XY plane, then repeating the same operation. 

Stuart

bisector (1).dgn

its sort of half way there, the bi sector CS points need to be on the 3d line at the line intersections. I can then attach my cell to it.

Pop a coordinate system back on the 3D vertex and project the point back up to that coordinate systems XY Plane. There will be a shift in the indices number but you can overcome that with the expression. 

8713.bisector (1).dgn

Here a Version using a sheared CS. 

function (PolyLine P_track)
{
    for (int i = 1; i < P_track.Vertices.Count-1 ; ++i)
    {
        Point dir_point = new Point(this);
        CoordinateSystem shear_cs = new CoordinateSystem(this);
        shear_cs.ByOriginPrimarySecondaryDirections(P_track.Vertices[i],P_track.Vertices[i-1],AxisOption.X,P_track.Vertices[i+1],AxisOption.Y,TransformOption.Sheared);
        double x1 = shear_cs.ShearAngle/2;
        dir_point.ByCartesianCoordinates(shear_cs,1,1,0);
        Line angle_line = new Line(this);
        angle_line.ByStartPointDirectionLength(P_track.Vertices[i],dir_point, 10);
    }
}