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<?xml-stylesheet type="text/xsl" href="https://communities.bentley.com/cfs-file/__key/system/syndication/rss.xsl" media="screen"?><rss version="2.0" xmlns:dc="http://purl.org/dc/elements/1.1/" xmlns:slash="http://purl.org/rss/1.0/modules/slash/" xmlns:wfw="http://wellformedweb.org/CommentAPI/"><channel><title>RAM Connection - Column Splice Moment Connection (Flange-plated) &amp;amp; Single Shear Plate</title><link>https://communities.bentley.com/products/ram-staad/f/ram-staad-forum/109750/ram-connection---column-splice-moment-connection-flange-plated-single-shear-plate</link><description>I am designing a column splice in RAM Connection. Both columns are W10x49 A992 Gr50. Shear = 50 kips, Axial = -300 kips, M33 = 150 kip*ft. After designing the problem, I obtain results with demand values I do not know. 
 How did RAM Connection calculate</description><dc:language>en-US</dc:language><generator>Telligent Community 12</generator><item><title>RE: RAM Connection - Column Splice Moment Connection (Flange-plated) &amp; Single Shear Plate</title><link>https://communities.bentley.com/thread/334168?ContentTypeID=1</link><pubDate>Wed, 12 Aug 2015 16:16:41 GMT</pubDate><guid isPermaLink="false">6dad98f5-dbc9-4c4d-a9ba-e9da8dc6aa8e:7ae6ddda-1cd0-40fd-aed5-5d5a0d9d2b7e</guid><dc:creator>Seth Guthrie</dc:creator><description>AISC 360 says that the full area (of the top, smaller column) is in bearing, so we prorate the flange force based on that. Note, it&amp;#39;s actually less conservative the way you wrote above; 180 -150 is only 30 kips&lt;div style="clear:both;"&gt;&lt;/div&gt;</description></item><item><title>RE: RAM Connection - Column Splice Moment Connection (Flange-plated) &amp; Single Shear Plate</title><link>https://communities.bentley.com/thread/334165?ContentTypeID=1</link><pubDate>Wed, 12 Aug 2015 16:11:30 GMT</pubDate><guid isPermaLink="false">6dad98f5-dbc9-4c4d-a9ba-e9da8dc6aa8e:995dab1f-5a3c-435c-8b95-35ff98f80e71</guid><dc:creator>Quenton Wattinger</dc:creator><description>Thank you for the explanation! I now understand where the number is coming from. But why isn&amp;#39;t the program calculating the demand flange force using the below equation?&lt;br /&gt;
&lt;br /&gt;
Demand Flange Force = (Pu/2)+(Mu/moment arm between flange forces)&lt;br /&gt;
&lt;br /&gt;
This calculates a more conservative flange force to compare the capacity to.&lt;div style="clear:both;"&gt;&lt;/div&gt;</description></item><item><title>RE: RAM Connection - Column Splice Moment Connection (Flange-plated) &amp; Single Shear Plate</title><link>https://communities.bentley.com/thread/334162?ContentTypeID=1</link><pubDate>Wed, 12 Aug 2015 15:55:54 GMT</pubDate><guid isPermaLink="false">6dad98f5-dbc9-4c4d-a9ba-e9da8dc6aa8e:2610f927-25d8-434f-ac8d-e58a76304076</guid><dc:creator>Seth Guthrie</dc:creator><description>&lt;p&gt;The program is coming up with the tensile flange force. In your case:&lt;/p&gt;
&lt;p style="margin-left:30px;"&gt;Moment: 150 kft * 12 = 1,800 k-in / 10 &amp;quot; (distance btw flanges) = 180 kips tension/compression per flange due to moment&lt;/p&gt;
&lt;p style="margin-left:30px;"&gt;Axial: 300 k * flange area/total area = 300 k * 37% = 111 kips (compression)&lt;/p&gt;
&lt;p style="margin-left:30px;"&gt;Max tension = 180 - 111 = 69 kips.&amp;nbsp;&lt;/p&gt;
&lt;p&gt;For compression the section is assumed to bear directly as indicated in the AISC Spec.&lt;/p&gt;
&lt;p&gt;Shear is entirely resisted by the other part of the joint.&lt;/p&gt;&lt;div style="clear:both;"&gt;&lt;/div&gt;</description></item></channel></rss>