I am designing a column splice in RAM Connection. Both columns are W10x49 A992 Gr50. Shear = 50 kips, Axial = -300 kips, M33 = 150 kip*ft. After designing the problem, I obtain results with demand values I do not know.
How did RAM Connection calculate the demands in the second photo?
See pictures attached
Answer Verified By: Quenton Wattinger
The program is coming up with the tensile flange force. In your case:
Moment: 150 kft * 12 = 1,800 k-in / 10 " (distance btw flanges) = 180 kips tension/compression per flange due to moment
Axial: 300 k * flange area/total area = 300 k * 37% = 111 kips (compression)
Max tension = 180 - 111 = 69 kips.
For compression the section is assumed to bear directly as indicated in the AISC Spec.
Shear is entirely resisted by the other part of the joint.