I just started using Steel design parameters...
Pls. help me out to give proper Lx, Ly & Lz values for the beams in model attached.
Some more queries :
1) Whether all Lx,Ly & Lz are required to define in model ?
2) Whether for columns Lx,Ly & Lz to be defined.
3) My live load a live load of 7KN/m2 on fifth floor . How to apply it on the beams?
Model details
STAAD SPACESTART JOB INFORMATIONENGINEER DATE 12-Aug-14END JOB INFORMATIONINPUT WIDTH 79UNIT METER KNJOINT COORDINATES1 0 0 0; 2 0 0 3.5; 3 3.5 0 0; 4 3.5 0 3.5; 5 0 4 0; 6 0 4 3.5; 7 3.5 4 0;8 3.5 4 3.5; 9 0 8 0; 10 0 8 3.5; 11 3.5 8 0; 12 3.5 8 3.5; 13 0 12 0;14 0 12 3.5; 15 3.5 12 0; 16 3.5 12 3.5; 17 0 16 0; 18 0 16 3.5; 19 3.5 16 0;20 3.5 16 3.5; 21 1.75 16 3.5; 22 0 16 1.75; 23 1.75 16 0; 24 3.5 16 1.75;MEMBER INCIDENCES1 1 5; 2 5 6; 3 6 2; 4 5 7; 5 7 8; 6 8 6; 7 8 4; 8 7 3; 9 9 10; 10 9 11;11 11 12; 12 12 10; 13 13 14; 14 13 15; 15 15 16; 16 16 14; 17 9 5; 18 10 6;19 12 8; 20 11 7; 21 13 9; 22 14 10; 23 15 11; 24 16 12; 25 17 22; 26 17 23;27 19 24; 28 20 21; 29 17 13; 30 18 14; 31 20 16; 32 19 15; 33 21 18; 34 22 18;35 23 19; 36 24 20;START USER TABLETABLE 1 FINALCOL.UPTTABLE 2 ISMB300FIN.UPTTABLE 3 BEAM600.UPTENDDEFINE MATERIAL STARTISOTROPIC STEELE 2.05e+008POISSON 0.3DENSITY 76.8195ALPHA 1.2e-005DAMP 0.03TYPE STEELSTRENGTH FY 253200 FU 407800 RY 1.5 RT 1.2END DEFINE MATERIALMEMBER PROPERTY INDIAN2 4 TO 6 9 TO 16 25 TO 28 33 TO 36 TABLE ST ISMB3001 3 7 8 17 TO 24 29 TO 32 TABLE ST ISMB600CONSTANTSMATERIAL STEEL ALLSUPPORTS1 TO 4 FIXEDLOAD 1 DEAD + LIVEJOINT LOAD21 TO 24 FY -10SELFWEIGHT Y -1 PERFORM ANALYSISPERFORM ANALYSIS PRINT STATICS CHECKPARAMETER 1CODE IS800 LSDCMX 0.9 MEMB 1 3 7 8 17 TO 24 29 TO 32CMZ 0.9 MEMB 1 3 7 8 17 TO 24 29 TO 32CMY 0.9 MEMB 1 3 7 8 17 TO 24 29 TO 32FU 420000 ALLFYLD 250000 ALLKX 1 MEMB 1 3 7 8 17 TO 24 29 TO 32KY 1 MEMB 1 3 7 8 17 TO 24 29 TO 32KZ 1 MEMB 1 3 7 8 17 TO 24 29 TO 32FINISH
Pls. help me out to understand the concept on design parameters(Lx,Ly,Lz)
What if for a member both the parameters - Ky and Ly are used?
For ex., A member is having length L = 0.80 m
Design parameters assigned to this member are: KY = 0.85 and LY = 1.4
what will be the effective length used for the calculation?
I was going through the STAAD documentation and found this:
Source: here
What parameters are used for defining unsupported length in IS 800 LSD?
It was UNL in IS 800 but I think there is no provision of UNL in IS 800 LSD.
Thank you ..as specified in tech. reference LX = Effective Length for Lateral Torsional Buckling , then in the model only Lx is sufficient for beams ???
whether LTB takes cares of compression flange yielding, Tension flange yielding failure also .... Can you pls provide the parameters for the above model i have discussed for my understanding.