I am struggling to get anchorage lengths to work in RAM concept.
I understand that when calculating if L or hook anchorages are adequate, RAM checks if there is sufficient space to incorporate a L bar (Lbd+ 1.125d) - if there is insufficient space to anchor in this way, a hook is selected.
What parameter does RAM use to define if there is sufficient space to place an L bar? I have a deep slab bearing into a concrete wall (above and below the slab) however RAM is saying that an L bar anchorage will not work.
Does RAM allow for the L bars to be turned up the wall, or does it base the physical size on the slab depth only?
I there any way around this?
The program is checking a specific design section and checking the distance from that section to the slab edge -3" cover typically. See the program manual section 55.2 "Development lengths / anchorage" and 55.3 "How RAM Concept lays out longitudinal program reinforcement" for more.
The program does not consider which way a hook needs to go to fit in the concrete, nor that hooks could go up or down into columns or walls.
OK. But is it onty the edge distance that is taken into consideration - for example i have a 1000mm deep slab. Bottom bars can be returned as L bars to within the cover of the top surface, which is a substantial development length. Does the program take this into account when determining anchorage/development beyond the section?
sorry but the only issues i ever seem to have with RAM are to do with anchorage.
The program assumes the hook will fit, even if it has to be rotated to be almost parallel to the slab plane. What it checks is if ldh is fully or partially achieved. If the capacity at the first section requires even more developed reinforcement than hooked bars can provide, then an anchor is used.