Torsion for Dead Load?

Hello,

I have a very simple model in STAAD right now. I don't understand why STAAD is showing Torsion in some members even for Load Case 1 which is a Dead Load case. Can someone please explain this.

Thanks

STAAD SPACE
START JOB INFORMATION
ENGINEER DATE 18-Jun-19
END JOB INFORMATION
INPUT WIDTH 79
UNIT FEET KIP
JOINT COORDINATES
1 0 0 0; 2 6.5 0 0; 3 6.5 0 6.5; 4 0 0 6.5; 5 0 12.5 0; 6 0 12.5 6.5;
7 6.5 9.5 0; 8 6.5 9.5 6.5; 9 0 8 0; 10 0 8 6.5; 11 6.5 8 0; 12 6.5 8 6.5;
13 -0.25 0 6.5; 14 -0.25 0 0; 15 6.75 0 0; 16 6.75 0 6.5; 17 0 3 0; 18 0 3 6.5;
19 6.5 3 6.5; 20 6.5 3 0;
MEMBER INCIDENCES
1 1 2; 3 4 3; 5 5 9; 6 6 10; 7 2 20; 8 3 19; 9 5 7; 10 6 8; 11 7 8; 12 5 6;
13 10 18; 14 11 7; 15 12 8; 16 9 10; 17 10 12; 18 11 12; 19 9 11; 20 9 17;
21 14 1; 22 13 4; 23 2 15; 24 3 16; 25 17 1; 26 18 4; 27 17 18; 28 19 12;
29 18 19; 30 20 11; 31 20 19; 32 17 20;
DEFINE MATERIAL START
ISOTROPIC STEEL
E 4.176e+006
POISSON 0.3
DENSITY 0.489024
ALPHA 6e-006
DAMP 0.03
TYPE STEEL
STRENGTH FY 5184 FU 8352 RY 1.5 RT 1.2
END DEFINE MATERIAL
MEMBER PROPERTY AMERICAN
1 3 21 TO 24 TABLE ST W10X22
5 TO 8 13 TO 20 25 TO 32 TABLE ST HSST3X3X0.375
9 TO 12 TABLE ST HSSP1.660X0.14
CONSTANTS
MATERIAL STEEL ALL
SUPPORTS
13 TO 16 PINNED
LOAD 1 LOADTYPE Dead TITLE DEAD
SELFWEIGHT Y -1 LIST 1 3 5 TO 8 13 TO 32
MEMBER LOAD
16 TO 19 27 29 31 32 UNI GY -0.01625
LOAD 2 LOADTYPE Snow TITLE SNOW SLOPE
JOINT LOAD
5 TO 8 FY -0.2
LOAD 3 LOADTYPE Ice TITLE ICE
JOINT LOAD
5 TO 8 FY -0.152
LOAD 4 LOADTYPE Wind TITLE WINDX+
MEMBER LOAD
5 6 13 16 20 25 TO 27 UNI GX 0.01
1 3 UNI GX 0.21
1 3 UMOM GZ -1.12
LOAD 5 LOADTYPE Wind TITLE WINDX-
MEMBER LOAD
7 8 14 15 18 28 30 31 UNI GX -0.01
1 3 UNI GX -0.21
1 3 UMOM GZ 1.12
LOAD 6 LOADTYPE Wind TITLE WINDZ+
MEMBER LOAD
5 7 14 19 20 25 30 32 UNI GZ 0.01
1 3 UNI GZ 0.22
1 3 UMOM GX 1.21
LOAD 7 LOADTYPE Wind TITLE WINDZ-
MEMBER LOAD
6 8 13 15 17 26 28 29 UNI GZ -0.01
1 3 UNI GZ -0.22
1 3 UMOM GX -1.21
LOAD COMB 11 1.4D
1 1.4
LOAD COMB 12 1.2D+0.5S
1 1.2 3 0.5
LOAD COMB 13 1.2D+1.6S+0.8WX+
1 1.2 2 1.6 4 0.8
LOAD COMB 14 1.2D+1.6S+0.8WX-
1 1.2 2 1.6 5 0.8
LOAD COMB 15 1.2D+1.6S+0.8WZ+
1 1.2 2 1.6 6 0.8
LOAD COMB 16 1.2D+1.6S+0.8WZ-
1 1.2 2 1.6 7 0.8
LOAD COMB 17 1.2D+1.6WX++0.5S
1 1.2 4 1.6 2 0.5
LOAD COMB 18 1.2D+1.6WX-+0.5S
1 1.2 5 1.6 2 0.5
LOAD COMB 19 1.2D+1.6WZ++0.5S
1 1.2 6 1.6 2 0.5
LOAD COMB 20 1.2D+1.6WZ-+0.5S
1 1.2 7 1.6 2 0.5
LOAD COMB 21 1.2D+0.2S
1 1.2 3 0.2
LOAD COMB 22 0.9D+1.6WX+
1 0.9 4 1.6
LOAD COMB 23 0.9D+1.6WX-
1 0.9 5 1.6
LOAD COMB 24 0.9D+1.6WZ+
1 0.9 6 1.6
LOAD COMB 25 0.9D+1.6WZ-
1 0.9 7 1.6
LOAD COMB 26 0.9D
1 0.9
LOAD COMB 31 1.2D+0.2I+0.5S
1 1.2 3 0.2 2 0.5
LOAD COMB 32 1.2D+I+0.5S
1 1.2 3 1.6 2 0.5
LOAD COMB 33 0.9D+I
1 0.9 3 1.0
LOAD COMB 41 D
1 1.0
LOAD COMB 42 D+S
1 1.0 2 1.0
LOAD COMB 43 D+0.75S
1 1.0 2 0.75
LOAD COMB 44 D+WX+
1 1.0 4 1.0
LOAD COMB 45 D+WX-
1 1.0 5 1.0
LOAD COMB 46 D+WZ+
1 1.0 6 1.0
LOAD COMB 47 D+WZ-
1 1.0 7 1.0
LOAD COMB 48 D+0.75WX++0.75S
1 1.0 4 0.75 2 0.75
LOAD COMB 49 D+0.75WX-+0.75S
1 1.0 5 0.75 2 0.75
LOAD COMB 50 D+0.75WZ++0.75S
1 1.0 6 0.75 2 0.75
LOAD COMB 51 D+0.75WZ-+0.75S
1 1.0 7 0.75 2 0.75
LOAD COMB 52 0.6D+WX+
1 0.6 4 1.0
LOAD COMB 53 0.6D+WX-
1 0.6 5 1.0
LOAD COMB 54 0.6D+WZ+
1 0.6 6 1.0
LOAD COMB 55 0.6D+WZ-
1 0.6 7 1.0
LOAD COMB 56 0.6D
1 0.6
LOAD COMB 61 D+0.7I
1 1.0 3 0.7
LOAD COMB 62 D+0.7I+S
1 1.0 3 0.7 2 1.0
LOAD COMB 63 0.6D+0.7I
1 0.6 3 0.7
PERFORM ANALYSIS
DEFINE ENVELOPE
41 TO 56 61 TO 63 ENVELOPE 1 TYPE SERVICEABILITY
11 TO 26 31 TO 33 ENVELOPE 2 TYPE STRENGTH
END DEFINE ENVELOPE
LOAD LIST ENV 1 2
PARAMETER 1
CODE AISC UNIFIED 2010
METHOD LRFD
FYLD 6624 MEMB 5 TO 8 13 15 TO 20 25 TO 32
FYLD 7200 MEMB 1 3 21 TO 24
FU 8352 MEMB 5 TO 8 13 15 TO 20 25 TO 32
FU 9360 MEMB 1 3 21 TO 24
RATIO 0.8 MEMB 1 3 5 TO 8 13 TO 32
DJ2 1 MEMB 5 20 25
DJ1 5 MEMB 5 20 25
DJ2 4 MEMB 6 13 26
DJ1 6 MEMB 6 13 26
DJ2 3 MEMB 8 15 28
DJ1 8 MEMB 8 15 28
DJ2 2 MEMB 7 14 30
DJ1 7 MEMB 7 14 30
DJ2 16 MEMB 3 22 24
DJ1 13 MEMB 3 22 24
DJ2 15 MEMB 1 21 23
DJ1 14 MEMB 1 21 23
DFF 360 MEMB 1 3 5 TO 8 13 TO 32
LZ 5 MEMB 5 TO 8 13 TO 15 20 25 26 28 30
LY 5 MEMB 5 TO 8 13 TO 15 20 25 26 28 30
UNT 0 MEMB 9 TO 12
CHECK CODE MEMB 1 3 5 TO 8 13 TO 32
FINISH

Parents
  • This structure has tubes which are torsionally stiff so it's not unusual that they would pick up some torque. What I find perplexing is the torque you applied in load cases 6 and 7. Of course the beams with torque applied directly to them are going to have torsion in them. What are you modeling with this applied torque?

  • I get that the beams will get torsion when I am applying it there, but why am I seeing a Torsion for a Dead Load is my concern. There is no applied torque for that case and no out of the plane loads/moment. 

    For load case 6, 7 I will have an overturning moment because of wind in that direction. So I distributed the moment for 2 beams at the bottom. Is this wrong load application?

  • It's a matter of stiffness. Look at node 9, load case 1. It has four members framing into. The moments at this node must sum to zero. Member 16 has a major axis moment at node 9 of -1.003 k-in. Members 5 and 20 have a 0.615 k-in and 0.368 k-in minor axis moment which resist the end moment in member 16. That leaves 0.02 k-in unaccounted for. Guess where it went. Yep, torsion in member 19. Statics works once again! If you would have been doing this by hand, you would neglected the torsional stiffness in member 19 and divided that 0.02 k-in between the two column members. Computers think of everything though. (Well, more or less.) BTW, this tiny bit of torque is nothing to get your panties in a wad about.

    Regarding load case 6 and 7. That is incorrect to apply a moment. The lateral forces being above the base is what applies the overturning moment. You don't have to add your own.

  • I get that Thank You.

    Actually I haven't applied lateral load by wind on the structure itself. I converted that load to base shear and overturning moment at the base beams. The reason to do that is there is a panel which will transfer load exactly like that. But that panel is not modeled as it's not a structural member. I didn't knew how to apply lateral load in a dummy beam in staad so used this procedure. Is there any other way?

  • Should I converted the moment in couple forces and apply Uniform force upwards on one beam and downward on the back beam? That should work, it will not generate this uneven torsion.

  • Lunch time is over so I gotta get back to work. I can't imagine a panel that would only impart load to the bottom beam. Maybe you can post a drawing of what it is you're trying to model.

Reply Children
No Data