https://communities.bentley.com/products/ram-staad/f/ram-staad-forum/214369/how-to-design-a-slant-beam-inclined-ramp-beam-in-staad-pro-c-e-workflowIam interested to know if i can design a slanting reinforced concrete beam as shown in figure below, and perform its deflection check. This can not be done in RCDC because RCDC design beams at a constant heighten-USTelligent Community 12https://communities.bentley.com/thread/653833?ContentTypeID=1Mon, 07 Jun 2021 07:51:47 GMT6dad98f5-dbc9-4c4d-a9ba-e9da8dc6aa8e:0589b6ba-5113-479d-a941-abbbd3a1b47drtully14<p>You have the option in Add New : Load Items, for Plate Loads, to add Pressure on Full Plate in Local X or Local Y axis.</p><div style="clear:both;"></div>https://communities.bentley.com/thread/653831?ContentTypeID=1Mon, 07 Jun 2021 07:48:24 GMT6dad98f5-dbc9-4c4d-a9ba-e9da8dc6aa8e:b8cd45c5-ea6c-42ae-818d-2d570cb053d6Joseph Lucas Magare<p>ok, what about horizontal plate load?</p><div style="clear:both;"></div>https://communities.bentley.com/thread/653826?ContentTypeID=1Mon, 07 Jun 2021 07:43:10 GMT6dad98f5-dbc9-4c4d-a9ba-e9da8dc6aa8e:2caff95d-50d8-4db1-a413-9ce7596441f6Joseph Lucas Magare<p>my ramp has side beams which supports the ramp, i can resolve plate load to be Pcos(theta) that will be my vertical plate load which can be assigned as GY or Locally Z direction, what about my horizontal plate load which is Psin(theta) how will i apply it on the plate?</p><div style="clear:both;"></div>https://communities.bentley.com/thread/653825?ContentTypeID=1Mon, 07 Jun 2021 07:42:32 GMT6dad98f5-dbc9-4c4d-a9ba-e9da8dc6aa8e:090459ec-f7e6-410c-8f26-0fc805d2f4aertully14<p>You can apply this in STAAD.Pro by applying a Member Load - Uniform Force in Direction X (Local).</p><div style="clear:both;"></div>https://communities.bentley.com/thread/653823?ContentTypeID=1Mon, 07 Jun 2021 07:32:37 GMT6dad98f5-dbc9-4c4d-a9ba-e9da8dc6aa8e:536a8c1d-5273-45c5-9cf2-ec76b1b5fb77Joseph Lucas Magare<p>How do i&nbsp; apply horizontal load on a beam?</p><div style="clear:both;"></div>https://communities.bentley.com/thread/653055?ContentTypeID=1Wed, 02 Jun 2021 08:31:10 GMT6dad98f5-dbc9-4c4d-a9ba-e9da8dc6aa8e:3058cf4c-99e2-43df-b022-905103ec9f2artully14<p>If the angle of&nbsp; the slope is theta then model the beam as horizontal and if the vertical load on the slope was P then this is resolved as a vertical load of Pcos(theta) and the horizontal load becomes Psin(theta).&nbsp;</p><div style="clear:both;"></div>https://communities.bentley.com/thread/653051?ContentTypeID=1Wed, 02 Jun 2021 08:18:35 GMT6dad98f5-dbc9-4c4d-a9ba-e9da8dc6aa8e:78c303b9-f4f3-438a-b481-009402a3ef81Joseph Lucas Magare<p>How do i do that?</p><div style="clear:both;"></div>https://communities.bentley.com/thread/653047?ContentTypeID=1Wed, 02 Jun 2021 08:11:41 GMT6dad98f5-dbc9-4c4d-a9ba-e9da8dc6aa8e:11bd7bb7-c344-42ea-afba-6d6ef61a397crtully14<p>One solution for the design would be to design the beam as horizontal and split the vertical load on the slope into a vertical and horizontal load on the beam.</p><div style="clear:both;"></div>https://communities.bentley.com/thread/651958?ContentTypeID=1Wed, 26 May 2021 14:30:31 GMT6dad98f5-dbc9-4c4d-a9ba-e9da8dc6aa8e:d736e05d-5115-4e80-8495-2c67865247f2Joseph Lucas Magare<p><a href="/members/7d4d290f_2d00_f067_2d00_4793_2d00_8d57_2d00_2a30f35813f2">Sabrina Tedeschi</a></p> <p><a href="/members/99733e82_2d00_0b5d_2d00_4d13_2d00_9244_2d00_098c0f62230a">Sabrina Tedeschi</a></p> <p><a href="/members/9dfee627_2d00_88ae_2d00_43d5_2d00_80b7_2d00_d25ba644dab9">Badreddine Ziane</a></p><div style="clear:both;"></div>https://communities.bentley.com/thread/651807?ContentTypeID=1Wed, 26 May 2021 05:49:05 GMT6dad98f5-dbc9-4c4d-a9ba-e9da8dc6aa8e:1aa63c76-f27b-4c37-a1bc-f4cec16180dcJoseph Lucas Magare<p>?</p><div style="clear:both;"></div>