Horizontal member load at an angle

I think you should be able to achieve this by using the Inclined Load option in the Nodal Loads:

Thanks for your response. Is there a way of adding it to the center of the beam and not the node?

You may use a concentrated member load, but it cannot be applied in inclined direction - you would need to apply the load in 2 components in the X and Z global direction.

Thanks, I'll try the option using member load. I'm guessing some of the loads have to be applied in both the positive and negative direction. Is this correct?

I tried the nodal load method and this is what I get for my moment. Not sure if this moment diagram makes sense. What do you think? The ring beam is sitting directly on a plate wall.

My apologies, I forgot that you can apply the Concentrated Load on a member with respect to its local Y or Z axis, so that should work in your case. Just you need to set the d1 parameter with a distance to member's center.

My apologies, I forgot that you can apply the Concentrated Load on a member with respect to its local Y or Z axis, so that should work in your case. Just you need to set the d1 parameter with a distance to member's center.

ok - I applied it along the local x and z axis of the member like this. This is the load and this is the result I got from it. Is this okay?

I'm guessing I can also apply it to the local x and z of the member as I show in my Dec 1 reply (left side image) above?

Yes, a load can be applied along the local X, Y and Z axes. Attached is a simple file to illustrate this.
8358.str2.std

Thanks Kris