Horizontal member load at an angle

RE: Horizontal member load at an angle

John C — Tue, 07 Dec 2021 17:13:40 GMT

Thanks Kris

RE: Horizontal member load at an angle

Kris Sathia — Tue, 07 Dec 2021 07:06:41 GMT

Yes, a load can be applied along the local X, Y and Z axes. Attached is a simple file to illustrate this.
communities.bentley.com/.../8358.str2.std

RE: Horizontal member load at an angle

John C — Mon, 06 Dec 2021 12:30:04 GMT

I'm guessing I can also apply it to the local x and z of the member as I show in my Dec 1 reply (left side image) above?

RE: Horizontal member load at an angle

John C — Wed, 01 Dec 2021 15:12:26 GMT

ok - I applied it along the local x and z axis of the member like this. This is the load and this is the result I got from it. Is this okay?

RE: Horizontal member load at an angle

Modestas — Wed, 01 Dec 2021 13:51:31 GMT

My apologies, I forgot that you can apply the Concentrated Load on a member with respect to its local Y or Z axis, so that should work in your case. Just you need to set the d1 parameter with a distance to member's center.

RE: Horizontal member load at an angle

John C — Wed, 01 Dec 2021 13:15:43 GMT

Thanks, I'll try the option using member load. I'm guessing some of the loads have to be applied in both the positive and negative direction. Is this correct?

I tried the nodal load method and this is what I get for my moment. Not sure if this moment diagram makes sense. What do you think? The ring beam is sitting directly on a plate wall.

RE: Horizontal member load at an angle

Modestas — Wed, 01 Dec 2021 12:58:39 GMT

You may use a concentrated member load, but it cannot be applied in inclined direction - you would need to apply the load in 2 components in the X and Z global direction.

RE: Horizontal member load at an angle

John C — Wed, 01 Dec 2021 11:33:10 GMT

Thanks for your response. Is there a way of adding it to the center of the beam and not the node?

RE: Horizontal member load at an angle

Modestas — Wed, 01 Dec 2021 08:24:08 GMT

I think you should be able to achieve this by using the Inclined Load option in the Nodal Loads: