https://communities.bentley.com/products/ram-staad/f/ram-staad-forum/228042/integration-time-step-in-time-history-analysisHow the default value of Integration time step of 0.0013888 sec is decided in Staad?. what is the basis for it. Could any one please help out?en-USTelligent Community 12https://communities.bentley.com/thread/705341?ContentTypeID=1Thu, 07 Apr 2022 06:11:55 GMT6dad98f5-dbc9-4c4d-a9ba-e9da8dc6aa8e:1cb17606-a96d-4c38-8485-14833533b5b5Santosh K<p>Thank you!</p><div style="clear:both;"></div>https://communities.bentley.com/thread/705336?ContentTypeID=1Thu, 07 Apr 2022 06:03:35 GMT6dad98f5-dbc9-4c4d-a9ba-e9da8dc6aa8e:3da3c795-4968-445e-a30e-f8d6eb493da8Aswathi A<p>The rule of thumb is that to capture the contribution of a mode, DT must be smaller than (1/10th) the period of that mode. With high-frequency modes, the period of the modes will be so small that the default DT may become larger than one cycle of that mode&rsquo;s response. It is not possible to calculate the response for that mode accurately with that DT.</p> <p>&nbsp;</p> <p>0.001388 is obtained as 1/10th the period of 72 cps. 72 cps was chosen as a number that is high enough that most structures won&#39;t have a significant mode with such a high frequency.</p><div style="clear:both;"></div>