Hello,
I am verifying the computed corner pressures of a combined footing with 3 columns subjected to different magnitudes of axial loads and moments. However, I am getting a large discrepancy between the hand calculation and software results.
Loading Combination 04 - Net Pressure at Corners
Length = 12m
Width = 2.5m
Soil Unit Weight = 17.6 kN/m3
Depth to Footing Base = 2.5m
Footing Self Weight = 344.99kN
Top Soil Weight = 1029.56kN
Column 1:
Fy = 150kN
Mx = 60kN-m
Mz = 60kN-m
Column 2:
Fy = 90kN
Mx = -25kN-m
Mz = 40kN-m
Column 3:
Mx = 30kN-m
Mz = 70kN-m
Determine Total Net Axial Pressure:
Gross Pressure = [(150+90+90)+(344.99+1029.56)/(12*2.5)] = 56.818 kPa
Net Pressure = 56.818 kPa – (17.6*2.5) = 12.818kPa
Determine Total Moments:
Summation of Mx = 60 – 25 + 30 = 65kN-m
Summation of Mz = 60 + 40 + 70 = 170kN-m
Calculate Z:
Zx = 12* (2.5)^2 / 6 = 12.5 cu. m
Zz = 2.5* (12)^2 / 6 = 60 cu. m
Pressures at the corner:
12.818kPa + (65/12.5) + (170/60) = 20.851 kPa
12.818kPa + (65/12.5) - (170/60) = 15.185 kPa
12.818kPa - (65/12.5) + (170/60) = 10.451 kPa
12.818kPa - (65/12.5) - (170/60) = 4.785 kPa
delte.sfa
The loads from the 3 columns need to be replaced with a single set of loads acting thru a single column positioned at the CG of the footing. Since the P from the 3 columns are not the same, an extra MZ will be generated at the center of the footing. Take a look at the European combined footing example 2 for the procedure.
Answer Verified By: Louis Flores