HOW TO CALCULATE AXIAL BEARING IN RAM BASE PLATE CONNECTION DESIGN

Axial bearing                                                                        [kN/m2] 19046.77  5988.67    LC-517-16                   0.31                  DG1 3.1.1;

      A2 = ((B/N)*Ncs)*Ncs = ((600 [mm] /600 [mm] )*750 [mm] )*750 [mm]  = 5.63E+05 [mm2]                                  DG1 Sec 3.1.1

      A1 = B*N = 600 [mm] *600 [mm]  = 3.60E+05 [mm2]                                                                                         DG1 Sec 3.1.1

      fp, max = f*min(0.85*f'c*(A2/A1)1/2, 1.7*f'c) = 0.65*min(0.85*27.579 [N/mm2] *(1.563)1/2, 1.7*27.579 [N/mm2] ) = 19.047 [N/mm2]        DG1 3.1.1

I have checked Demand capacity for axial bearing for the perticular load case, but in RAM connection value does not match with manual calculation for per same load case.

i am sharing word file of RAM output with all load case.

manual value for the same load case is 4752.3 [kN/m2] load case LC-517-16

values are in Bold.

looking forward to your reply.M760A03_INPLACE_08-08-22_SQUARE.rtf