Indian Code - Steel Column Design

As per Indian - SP6(1), the column capacity (SAFE CONCENTRIC LOADS) of ISHB 350 for effective length of 4m = 1047.14KN

What is wrong with my coding ? Please help.

The Column found to be safe even with 10000 KN

Dany

STAAD PLANE
INPUT WIDTH 79
UNIT METER KN
JOINT COORDINATES
1 0 0 0; 2 0 4 0;
MEMBER INCIDENCES
1 1 2;
DEFINE MATERIAL START
ISOTROPIC STEEL
E 2.05e+008
POISSON 0.3
DENSITY 76.8195
ALPHA 1.2e-005
DAMP 0.03
END DEFINE MATERIAL
MEMBER PROPERTY INDIAN
1 TABLE ST ISHB350
CONSTANTS
MATERIAL STEEL ALL
SUPPORTS
1 2 PINNED
PRINT MEMBER INFORMATION LIST 1
LOAD 1 LOADTYPE Live  TITLE LOAD CASE 1
SELFWEIGHT Y -1 LIST 1
JOINT LOAD
2 FY -10000
PERFORM ANALYSIS
PRINT MEMBER FORCES
PARAMETER 1
CODE INDIAN
NSF 0.85 ALL
KY 1.2 ALL
RATIO 1 ALL
BEAM 0 ALL
PERFORM ANALYSIS
PARAMETER 2
CODE INDIAN
RATIO 1 ALL
BEAM 0 ALL
TRACK 1 ALL
CHECK CODE ALL
STEEL TAKE OFF LIST 1
PARAMETER 3
CODE INDIAN
FINISH

 

  • Dear Sir,

       It appears you have given the joint load at a pinned support. In that case, the load will directly go to the support and no load will go to the member. Hence, even if you increase the load, you are not getting changed result... Effective load on the section is only the selfweight...

    Arun

  • Dear Arun,

    The last two lines in command/input file i.e. PARAMETER 3, CODE INDIAN is in any way going to change the design. Is it not that input up to the line prior to the above is adequate to complete the design? This query is for my personal satisfaction.

  • Dany:

    Arun is correct.  The concentrated load is applied to a node which is pinned. Hence, all the concentrated load will flow to the pinned support, leaving the column section to wothstand only the load due to selfweight.

    Suresh:

    The last two lines are unnecessary. You will have the same output if you use the following command lines in the parameter block:

    STAAD PLANE

    INPUT WIDTH 79

    UNIT METER KN

    JOINT COORDINATES

    1 0 0 0; 2 0 4 0;

    MEMBER INCIDENCES

    1 1 2;

    DEFINE MATERIAL START

    ISOTROPIC STEEL

    E 2.05e+008

    POISSON 0.3

    DENSITY 76.8195

    ALPHA 1.2e-005

    DAMP 0.03

    END DEFINE MATERIAL

    MEMBER PROPERTY INDIAN

    1 TABLE ST ISHB350

    CONSTANTS

    MATERIAL STEEL ALL

    SUPPORTS

    1 2 PINNED

    PRINT MEMBER INFORMATION LIST 1

    LOAD 1 LOADTYPE Live  TITLE LOAD CASE 1

    SELFWEIGHT Y -1 LIST 1

    JOINT LOAD

    2 FY -10000

    PERFORM ANALYSIS

    PRINT MEMBER FORCES

    PARAMETER 1

    CODE INDIAN

    NSF 0.85 ALL

    KY 1.2 ALL

    RATIO 1 ALL

    BEAM 0 ALL

    TRACK 1 ALL

    PERFORM ANALYSIS

    CHECK CODE ALL

    STEEL TAKE OFF LIST 1

    FINISH

    Sudip Narayan Choudhury

  • Thanks a lot..

    The result almost same (1151KN instead of 1047.14KN) when keeping the effective length of the member same. ie 4m, using one end fixed and the other free.

    STAAD PLANE

    INPUT WIDTH 79

    UNIT METER KN

    JOINT COORDINATES

    1 0 0 0; 2 0 2 0;

    MEMBER INCIDENCES

    1 1 2;

    DEFINE MATERIAL START

    ISOTROPIC STEEL

    E 2.05e+008

    POISSON 0.3

    DENSITY 76.8195

    ALPHA 1.2e-005

    DAMP 0.03

    END DEFINE MATERIAL

    MEMBER PROPERTY INDIAN

    1 TABLE ST ISHB350

    CONSTANTS

    MATERIAL STEEL ALL

    SUPPORTS

    1 FIXED

    PRINT MEMBER INFORMATION LIST 1

    LOAD 1 LOADTYPE Live  TITLE LOAD CASE 1

    SELFWEIGHT Y -1 LIST 1

    JOINT LOAD

    2 FY -1150

    PERFORM ANALYSIS

    PRINT MEMBER FORCES

    PARAMETER 1

    CODE INDIAN

    NSF 0.85 ALL

    KY 1.2 ALL

    RATIO 1 ALL

    BEAM 0 ALL

    TRACK 1 ALL

    PERFORM ANALYSIS

    CHECK CODE ALL

    STEEL TAKE OFF LIST 1

    FINISH

  • Have you checked the column section after executing the design by Staad as to whether the section is same as assigned by you or it has been changed to some higher group? The difference of 1 kn in reaction from the load applied is because of self weight of the column.