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RAM | STAAD | ADINA Wiki Belgian National Annex Calculation as per EC3
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    Belgian National Annex Calculation as per EC3

       
      Applies To 
       
      Product(s): STAAD.Pro
      Version(s): All
      Environment:  N/A
      Area:  Wiki
      Subarea:  Belgian NA sample calculation as per EN 1993-1-1:2005
      Original Author: Anisurya Ghosh, BSW-Quality Assurance, Bentley Kolkata
       

     

     

     

     

     

     

     

     

    • Introduction:

    The following is a validation problem for a detailed calculation of the additional clauses for Belgian National Annex. (Belgian NA document: “NBN EN 1993-1-1:2005”)

    The Belgian National Annex implementation is a part of the Eurocode 3 design code (EN 1993-1-1:2005) in the Steel design module of STAAD.Pro.

    To invoke and use the Belgian National Annex, the user needs to set the value of the “NA” parameter to ‘8’.

    • Validation Problem:

     

             

     

    A European I section cantilever beam (HD320X127, S275 grade steel) , 5 m has been subjected to a concentrated point Load of 25 KN (FY) and concentrated moments 5 KN-m (MX) and 10 KN-m (MZ) at the free end.

     Outputs: MA= 10 KN-m, MB= 10 KN-m, SFA= 0 KN, SFB= 0 KN

     


    • Text Input Information:

    The following is the text input information of the STAAD model:

    STAAD SPACE

    START JOB INFORMATION

    ENGINEER DATE 21-Feb-14

    END JOB INFORMATION

    INPUT WIDTH 79

    UNIT METER KN
    JOINT COORDINATES
    1 0 0 0; 2 0 5 0;

    MEMBER INCIDENCES
    1 1 2;

    MEMBER PROPERTY EUROPEAN
    1 TABLE ST HD320X127

    DEFINE MATERIAL START
    ISOTROPIC STEEL
    E 2.05e+008
    POISSON 0.3
    DENSITY 76.8195
    ALPHA 1.2e-005
    DAMP 0.03
    END DEFINE MATERIAL
    CONSTANTS
    MATERIAL STEEL ALL

    SUPPORTS
    1 FIXED

    LOAD 1 LOADTYPE None TITLE LOAD CASE 1
    JOINT LOAD
    2 FY -25 MX 5 MZ 10
    PERFORM ANALYSIS

    PARAMETER 1
    CODE EN 1993-1-1:2005
    NA 8 ALL
    CMM 2 ALL
    C2 1.554 ALL
    FU 295000 ALL
    PY 275000 ALL
    *SGR 1 ALL
    CMN 0.7 ALL
    TRACK 2 ALL
    CHECK CODE ALL
    FINISH

     

     

    • Manual Calculation:

    We get: D= 320 mm, B= 300 mm, Tf= 20.5 mm, Tw= 11.5 mm, Iz= 30820 cm4, Iy= 9239 cm4,

     Zz= 1926.5 cm3, Zy= 615.93 cm3, J= 225.1 cm4, H= 2.069*10^12 mm6

    Moment Capacity, Mckd = Wply*fy/GM0 = 2149*1000*275/ (1*10^6) = 590.975 KN-m

    STAAD.Pro value is 591 KN-m [OK]

    Here, CMM=2.0, CMN=0.7

    So, C1 = 2.578, C2 = 1.554

    Π2*E*Iy/ (kL)2 = 7477192.555

    (k/kw)2 * (Iw/Iy) = 22394.19851

    (kL) 2 *G*It/( Π2*E*Iy) = 23736.5416

    C2Zg = 1.554*160 =248.64

    So, Mcr = 1540.6 KN-m

    STAAD.Pro value is 1541.5 KN-m [OK]

     

    From Belgian NA, λLT, 0 = 0.4, β = 0.75

    So, λLT = √ (wy*fy/Mcr) = √ (2149*10^3*275/1540600000) = 0.619355

    H/b = 320/300 = 1.067 < 2. So, from Table 6.5 of Eurocode 3, we get αLT = 0.34

    From Cl. 6.3.2.3 of Eurocode3, we get:

    ФLT = 0.5[1+αLT (λLT- λLT, 0) + β* λLT2]

            = 0.5*[1+0.34*(0.619355-0.4) +0.75*0.6193552] = 0.681141

    So, χLT = [ФLT+ √ (ФLT2- β* λLT2)]-1 = 0.908294

     

    So, MB = χLT*wy*fy/GM1 = 0.908294*2149000*275/(1*10^6)

    = 536.77 KN-m

    STAAD.Pro value is 536.8 KN-m [OK]

     

    NEd = 25 KN,                                                                      NRk = A*fy = 4435.75 KN

    My­Ed = 5 KN-m,               MzEd = 10 KN-m,             MyRk = 258.3 KN-m

    Determination of χy:

    h/b = 1.067 < 2 & tf = 20.5 mm < 100 mm

    So, for y-y axis, we will use curve ‘c’. Hence, α = 0.49 [Table 6.2, EC3]

    So, ф = 0.5[1+α (λ-0.2) +λ2)] = 0.9363

    Determination of χz:

    h/b = 1.067 < 2 & tf = 20.5 mm < 100 mm

    So, for z-z axis, we will use curve ‘c’. Hence, α = 0.34 [Table 6.2, EC3]

    So, ф = 0.5[1+α (λ-0.2) +λ2)] = 0.6266

    Compression Capacity = χy*NRk = 0.68087*4435.75 =3020.169 KN

    Compression Ratio = 25/3020.169 = 0.00828

    STAAD.Pro value for compression ratio is 0.008 [OK]

     

    Critical Axial Loads for Flexural and Flexural Torsional Buckling:

    From NCCI document SN001a-EN-FU:

    Here, y0 = z0 = 0

    iy = 75.68 mm, iz = 138.23 mm

    So, i02 = 75.682 + 138.232 = 24834.995

     

    Interaction Check:

    From Annex A, Table A.1 of EC3, we get the auxiliary terms:


    χLT = 0.908294

     Wz = wplz/welz = 2149/1926 = 1.1158

    Wy = wply/wely = 939/615.933 = 1.525 > 1.5, so, wy = 1.5

     CMM = 2.0, ψ=1.0

     

    Determination of λ0:

    C1=1, C2=0

    Mcr = 1605.96 KN

     

     

     


     


     


     

     

    • Summary:
    Item/Clause Unit STAAD.Pro Value Hand calculated Value
    Moment capacity KN-m 591 590.975
    Mcr KN-m 1541.5 1540.6
    MB KN-m 536.8 536.77
    Compression ratio - 0.008 0.00828
    NcrT KN 13898 13888.8
    NcrTF KN 13898 13888.8
    Cl. 6.3.3-661 - 0.038 0.0383
    Cl. 6.3.3-662 - 0.037 0.0377

     

    • EN 1993-1-1:2005
    • Belgian National Annex Calculation as per EC3
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    • History
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    • Anisurya Ghosh Created by Bentley Colleague Anisurya Ghosh
    • When: Fri, Feb 21 2014 4:50 AM
    • Steve Crabtree Last revision by Steve Crabtree
    • When: Mon, Jun 20 2016 11:55 AM
    • Revisions: 4
    • Comments: 0
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