The following is a validation problem for a detailed calculation of the Russian SP 16 I section design.
A 5 m long beam formed from a HD320X127 I section (Steel grade: S235), is checked for an applied UDL of -100 KN/m throughout the span.
STAAD PLANEINPUT WIDTH 79UNIT METER KNJOINT COORDINATES1 0 0 0; 2 5 0 0;MEMBER INCIDENCES1 1 2;DEFINE MATERIAL STARTISOTROPIC STEELE 2.05e+008POISSON 0.3DENSITY 76.8195ALPHA 1.2e-005DAMP 0.03TYPE STEELSTRENGTH FY 253200 FU 407800 RY 1.5 RT 1.2END DEFINE MATERIALMEMBER PROPERTY EUROPEAN1 TABLE ST HD320X127CONSTANTSMATERIAL STEEL ALLSUPPORTS1 PINNED2 FIXED BUT FX MZLOAD 1 LOADTYPE None TITLE LOAD CASE 1MEMBER LOAD1 UNI GY -100PERFORM ANALYSISPRINT FORCE ENVELOPE NSECTION 2 ALLPARAMETER 1CODE RUSSIANBEAM 1 ALL*CMN 5 ALLSGR 1 ALLGAMC2 1.1 ALLGAMC1 1.1 ALLTB 1 ALLDFF 200 ALL*BMT 100 ALLTRACK 2 ALLCHECK CODE ALLFINISH
Section Properties:
D= 320 mm, B= 300 mm, Tf= 20.5 mm, Tw= 11.5 mm, Ix= 30820 cm4, Iy= 9239 cm4,
Wx= 1926.5 cm3, Sx= 1070 cm3, J= 225.1 cm4, H= 2.069*10^12 mm6
Maximum Bending Moment = 312.5 KN-m
Material Properties:
S235
E = 206000 MPa, fy = 235 MPa, γc1 = 1.1, γc2 = 1.1
Check for Flexure:
We need to satisfy eqn. 41 of SNiP SP16.13330.2011:
M = 312.5, Wn,min = Wx = 1926.5 cm3, Ry = 235 MPa, γc2 = 1.1
Then, M/( Wn,min*Ry* γc) = 0.6275 < 1 (OK)
STAAD.Pro value is 0.628 [Matching]
Check for Shear:
We need to satisfy eqn. 42 of SNiP SP16.13330.2011:
Q = q.l/2 = 250 KN, S = 1070 cm3, I = 30820 cm4, Rs = 0.58*235 MPa, γc2 = 1.1, tw = 11.5 mm
Then, QS/(I*tw*Rs*γc) = 0.5034 < 1.0 (OK)
Check for Lateral Torsional Buckling:
We need to satisfy eqn. 42 of SNiP SP16.13330.2011
Check for Combined Shear & Flexure:
We need to satisfy eqn. 44 of SNiP SP16.13330.2011
Check for Deflection:
(5*100*54)/(384*206000*1000*30820*10-8) = 0.0128 m
STAAD.Pro value is 0.0128 m [Matching]
Maximum member deflection = l/200 = 0.025 m
Ratio = 0.0128/0.025 = 0.512
STAAD.Pro value is 0.51 [Matching]