Pushover Analysis of Steel Structure using STAAD (TN)

Modestas — Fri, 24 Mar 2023 11:58:47 GMT

Current Revision posted to RAM | STAAD | ADINA Wiki by Modestas on 3/24/2023 11:58:47 AM


	Applies To

	Product(s):	STAAD.Pro
	Version(s):	All
	Environment:	N/A
	Area:	Analysis Solutions
	Subarea:	Pushover Analysis
	Original Author:	Bentley Technical Support Group

Pushover Analysis

Steel Structure using STAAD

Bentley Systems

Mr. Kalavagunta Sreedhar

Definition

Pushover Analysis option will allow engineers to perform pushover analysis as per FEMA 356 : 2000 and ATC 40. Pushover analysis is a static, nonlinear procedure using simplified nonlinear technique to estimate seismic structural deformations. It is an incremental static analysis used to determine the force-displacement relationship, or the capacity curve, for a structure or structural element.

The analysis involves applying horizontal loads, in a prescribed pattern, to the structure incrementally, i.e. pushing the structure and plotting the total applied shear force and associated lateral displacement at each increment, until the structure or collapse condition.

Purpose of Pushover Analysis

It is expected that most buildings rehabilitated in accordance with a standard, would perform within the desired levels when subjected to the design earthquakes. Structures designed according to the existing seismic codes provide minimum safety to preserve life and in a major earthquake, they assure at least gravity-load-bearing elements of non-essential facilities will still function and provide some margin of safety. However, compliance with the standard does not guarantee such performance. They typically do not address performance of non-structural components neither provide differences in performance between different structural systems. This is because it cannot accurately estimate the inelastic strength and deformation of each member due to linear elastic analysis. Although an elastic analysis gives a good indication of elastic capacity of structures and indicates where first yielding will occur, it cannot predict failure mechanisms and account for redistribution of forces during progressive yielding.

To overcome this disadvantages different nonlinear static analysis method is used to estimate the inelastic seismic performance of structures, and as the result, the structural safety can be secured against an earthquake. Inelastic analysis procedures help demonstrate how buildings really work by identifying modes of failure and the potential for progressive collapse. The use of inelastic procedures for design and evaluation helps engineers to understand how structures will behave when subjected to major earthquakes, where it is assumed that the elastic capacity of the structure will be exceeded. This resolves some of the uncertainties associated with code and elastic procedures. The overall capacity of a structure depends on the strength and deformation capacities of the individual components of the structure. In order to determine capacities beyond the elastic limit some form of nonlinear analysis, like Pushover Analysis, is required.

Theory on which it is based

There are two nonlinear procedures using pushover methods:

a) Capacity Spectrum Method,

b) Displacement Coefficient Method.

In STAAD Displacement Coefficient method has been followed.

Displacement Coefficient Method is to find target displacement which is the maximum displacement that the structure is likely to be experienced during the design earthquake. It provides a numerical process for estimating the displacement demand on the structure, by using a bilinear representation of capacity curve and a series of modification factors, or coefficients, to calculate a target displacement. Refer Section 3.3.3.3.2 of FEMA 356: 2000 for detailed description of calculation of target displacement

Types of non-linearity

Both geometric and material non-linearities are considered in this static nonlinear pushover analysis.

Geometric non-linearity

This is a type of non-linearity where the structure is still elastic, but the effects of large deflections cause the geometry of the structure to change, so that linear elastic theory breaks down. Typical problems that lie in this category are the elastic instability of structures, such as in the Euler bulking of struts and the large deflection analysis of a beam-column member. In general, it can be said that for geometrical non-linearity, an axially applied compressive force in a member decreases its bending stiffness, but an axially applied tensile force increases its bending stiffness. In addition, P-Delta effect is also included in this concept.

Material non-linearity

In this type of non-linearity, material undergoes plastic deformation. Material non-linearity can be modeled as discrete hinges at a number of locations along the length of a frame (beam or column) element and a discrete hinge for a brace element as discrete material fibers distributed over the cross-section of the element, or as a series of material points throughout the element.

Frame element hinge properties

Discrete hinge properties for frame elements are based on FEMA-356 criteria as per Section 5.5.2.2.2.

Figure1.6 Generalized Force-Deformation Relationship for Components

Point A is the origin
Point B represents yielding. No deformation occurs in the hinge up to point B, regardless of the deformation value specified for point B. The displacement (rotation or axial elongation as the case may be) will be subtracted from the displacements at points C, D and E. Only plastic deformation beyond point B will be exhibited by hinge.
Point C represents ultimate capacity of plastic hinge. At this point hinge strength degradation begins (hinge starts shedding load) until it reaches point D.
Point D represents the residual strength of the plastic hinge. Beyond point D the component responds with substantially strength to point E.
Point E represnts total failure. At deformation greater than point E the plastic hinge will drop load to zero.

This diagram represent for those component actions which are ductile (e.g. Hinge formation for bending moment about local z axis of beam). For force-controlled action, Type 3 curve is followed. Refer Table C2-1 of FEMA 356 : 2000 for examples of possible deformation-controlled and force-controlled actions.

Lateral Load Distribution as per Section 3.3.3.2.3 Chapter 3 FEMA 356

Lateral load can be applied by following three methods.

Method 1

The vertical distribution of the base shear shall be as specified in this section for all buildings. The lateral load applied at any floor level x shall be determined in accordance with equation (1-8-1) and equation (1-8-2):

F_x = C_vxV …………………………. (1-8-1)

where

w_xh^k_x

C_vx = -------------------- …………………………. (1-8-2)

S w_ih^k_i

i = 1

Method 2

A vertical distribution proportional to the shape of the fundamental mode in the direction under consideration is performed. Use of this distribution shall be permitted only when more than 75% of the total mass participates in the fundamental mode in the direction under consideration, and the uniform distribution is also used.

w_xF_x

F_x = --------------- V

S w_iF_i

ⁱ^{= 1}

Method 3

A vertical distribution is performed consisting of lateral forces at each level proportional to the total mass at each level .

w_x

F_x = --------- V

S w_i

ⁱ^{= 1}

where,

C_vx = Vertical distribution factor

k = 2.0 for T 2.5 seconds ≥

= 1.0 for T 0.5 seconds ≤

Linear interpolation shall be used to calculate values of for intermediate values of k for

intermediate values of T.

V = User defined base shear

w_i = Portion of the total building weight W located on or assigned to floor level i

w_x = Portion of the total building weight W located on or assigned to floor level x

h_i = Height (in ft) from the base to floor level i

h_x = Height (in ft) from the base to floor level x

F_x= Amplitude of mode a floor level x

Masses

The method involves 2 matrices – the stiffness matrix and the mass matrix.

The stiffness matrix, usually called the [K] matrix, is assembled using data such as member and element lengths, member and element properties, modules of elasticity, poison’s ratio, member and element release, member offsets, support information, etc.

For assembling the mass matrix, called the [M] matrix, the input is weights, not masses. Internally, STAAD will convert weights to masses by dividing the input by “g” the acceleration due to gravity.

Example.

Illustrate the procedure and results find the bellow STAAD example

STAAD PLANE

START JOB INFORMATION

ENGINEER DATE 07-Oct-05

END JOB INFORMATION

INPUT WIDTH 79

UNIT INCHES KIP

JOINT COORDINATES

1 0 0 0; 2 0 118.11 0; 3 118.11 118.11 0; 4 118.11 0 0; 5 0 236.22 0;

6 118.11 236.22 0; 7 0 354.331 0; 8 118.11 354.331 0; 9 0 472.441 0;

10 118.11 472.441 0; 11 236.22 118.11 0; 12 236.22 0 0; 13 236.22 236.22 0;

14 236.22 354.331 0; 15 236.22 472.441 0;

MEMBER INCIDENCES

1 1 2; 2 2 3; 3 3 4; 4 2 5; 5 5 6; 6 6 3; 7 5 7; 8 7 8; 9 8 6; 10 7 9; 11 9 10;

12 10 8; 13 3 11; 14 6 13; 15 8 14; 16 10 15; 17 11 12; 18 13 11; 19 14 13;

20 15 14;

DEFINE MATERIAL START

ISOTROPIC STEEL

E 29732.7

POISSON 0.3

DENSITY 0.000283

ALPHA 1.2e-005

DAMP 0.03

END DEFINE MATERIAL

MEMBER PROPERTY AMERICAN

2 5 13 14 TABLE ST W16X26

8 11 15 16 TABLE ST W16X26

1 3 4 6 17 18 TABLE ST W24X55

7 9 10 12 19 20 TABLE ST W24X55

CONSTANTS

MATERIAL STEEL ALL

SUPPORTS

1 4 12 FIXED

DEFINE PUSHOVER DATA

FRAME 2

FYE 36.000000 ALL

GNONL 1

DISP X 15 JOINT 10

LDSTEP 250

SPECTRUM PARAMETERS

DAMPING 5.0000

SC 1

SS 1

S1 1

SAVE LOADSTEP RESULT DISP 0.010000

END PUSHOVER DATA

LOAD 1 LOADTYPE Gravity

SELFWEIGHT Y -1

MEMBER LOAD

2 5 8 11 13 TO 16 UNI GY -.4

PERFORM PUSHOVER ANALYSIS

FINISH

Figure 1: Capacity Curve for a Structure in STAAD.Pro V8i

Figure 2: Deflected shape at specified displacement for a Structure in STAAD.Pro V8i

Figure 4: Beam Hinge results for a Structure in STAAD.Pro V8i

STAAD Results

P R O B L E M S T A T I S T I C S

NUMBER OF JOINTS/MEMBER+ELEMENTS/SUPPORTS = 15/ 20/ 3

SOLVER USED IS THE IN-CORE ADVANCED SOLVER

TOTAL PRIMARY LOAD CASES = 1, TOTAL DEGREES OF FREEDOM = 36

NUMBER OF MODES REQUESTED = 1

NUMBER OF EXISTING MASSES IN THE MODEL = 24

NUMBER OF MODES THAT WILL BE USED = 1

STAAD PLANE -- PAGE NO. 3

CALCULATED FREQUENCIES FOR LOAD CASE 2

MODE FREQUENCY(CYCLES/SEC) PERIOD(SEC)

1 1.292 0.77396

MASS PARTICIPATION FACTORS IN PERCENT

MODE X Y Z SUMM-X SUMM-Y SUMM-Z

1 79.94 0.00 0.00 79.944 0.000 0.000

Tags: STAAD.Pro, TechNote, pushover analysis

Pushover Analysis of Steel Structure using STAAD (TN)

Steve Crabtree — Wed, 22 Jun 2016 17:14:30 GMT

Revision 6 posted to RAM | STAAD | ADINA Wiki by Steve Crabtree on 6/22/2016 5:14:30 PM


	Applies To

	Product(s):	STAAD.Pro
	Version(s):	All
	Environment:	N/A
	Area:	Pushover Analysis of Steel Structure using STAAD
	Subarea:	N/A
	Original Author:	Bentley Technical Support Group

Pushover Analysis

Steel Structure using STAAD

Bentley Systems

Mr. Kalavagunta Sreedhar

Definition

Purpose of Pushover Analysis

Theory on which it is based

There are two nonlinear procedures using pushover methods:

a) Capacity Spectrum Method,

b) Displacement Coefficient Method.

In STAAD Displacement Coefficient method has been followed.

Types of non-linearity

Both geometric and material non-linearities are considered in this static nonlinear pushover analysis.

Geometric non-linearity

Material non-linearity

Frame element hinge properties

Discrete hinge properties for frame elements are based on FEMA-356 criteria as per Section 5.5.2.2.2.

Figure1.6 Generalized Force-Deformation Relationship for Components

Point A is the origin
Point B represents yielding. No deformation occurs in the hinge up to point B, regardless of the deformation value specified for point B. The displacement (rotation or axial elongation as the case may be) will be subtracted from the displacements at points C, D and E. Only plastic deformation beyond point B will be exhibited by hinge.
Point C represents ultimate capacity of plastic hinge. At this point hinge strength degradation begins (hinge starts shedding load) until it reaches point D.
Point D represents the residual strength of the plastic hinge. Beyond point D the component responds with substantially strength to point E.
Point E represnts total failure. At deformation greater than point E the plastic hinge will drop load to zero.

Lateral Load Distribution as per Section 3.3.3.2.3 Chapter 3 FEMA 356

Lateral load can be applied by following three methods.

Method 1

F_x = C_vxV …………………………. (1-8-1)

where

w_xh^k_x

C_vx = -------------------- …………………………. (1-8-2)

S w_ih^k_i

i = 1

Method 2

w_xF_x

F_x = --------------- V

S w_iF_i

ⁱ^{= 1}

Method 3

A vertical distribution is performed consisting of lateral forces at each level proportional to the total mass at each level .

w_x

F_x = --------- V

S w_i

ⁱ^{= 1}

where,

C_vx = Vertical distribution factor

k = 2.0 for T 2.5 seconds ≥

= 1.0 for T 0.5 seconds ≤

Linear interpolation shall be used to calculate values of for intermediate values of k for

intermediate values of T.

V = User defined base shear

w_i = Portion of the total building weight W located on or assigned to floor level i

w_x = Portion of the total building weight W located on or assigned to floor level x

h_i = Height (in ft) from the base to floor level i

h_x = Height (in ft) from the base to floor level x

F_x= Amplitude of mode a floor level x

Masses

The method involves 2 matrices – the stiffness matrix and the mass matrix.

Example.

Illustrate the procedure and results find the bellow STAAD example

STAAD PLANE

START JOB INFORMATION

ENGINEER DATE 07-Oct-05

END JOB INFORMATION

INPUT WIDTH 79

UNIT INCHES KIP

JOINT COORDINATES

1 0 0 0; 2 0 118.11 0; 3 118.11 118.11 0; 4 118.11 0 0; 5 0 236.22 0;

6 118.11 236.22 0; 7 0 354.331 0; 8 118.11 354.331 0; 9 0 472.441 0;

10 118.11 472.441 0; 11 236.22 118.11 0; 12 236.22 0 0; 13 236.22 236.22 0;

14 236.22 354.331 0; 15 236.22 472.441 0;

MEMBER INCIDENCES

1 1 2; 2 2 3; 3 3 4; 4 2 5; 5 5 6; 6 6 3; 7 5 7; 8 7 8; 9 8 6; 10 7 9; 11 9 10;

12 10 8; 13 3 11; 14 6 13; 15 8 14; 16 10 15; 17 11 12; 18 13 11; 19 14 13;

20 15 14;

DEFINE MATERIAL START

ISOTROPIC STEEL

E 29732.7

POISSON 0.3

DENSITY 0.000283

ALPHA 1.2e-005

DAMP 0.03

END DEFINE MATERIAL

MEMBER PROPERTY AMERICAN

2 5 13 14 TABLE ST W16X26

8 11 15 16 TABLE ST W16X26

1 3 4 6 17 18 TABLE ST W24X55

7 9 10 12 19 20 TABLE ST W24X55

CONSTANTS

MATERIAL STEEL ALL

SUPPORTS

1 4 12 FIXED

DEFINE PUSHOVER DATA

FRAME 2

FYE 36.000000 ALL

GNONL 1

DISP X 15 JOINT 10

LDSTEP 250

SPECTRUM PARAMETERS

DAMPING 5.0000

SC 1

SS 1

S1 1

SAVE LOADSTEP RESULT DISP 0.010000

END PUSHOVER DATA

LOAD 1 LOADTYPE Gravity

SELFWEIGHT Y -1

MEMBER LOAD

2 5 8 11 13 TO 16 UNI GY -.4

PERFORM PUSHOVER ANALYSIS

FINISH

Figure 1: Capacity Curve for a Structure in STAAD.Pro V8i

Figure 2: Deflected shape at specified displacement for a Structure in STAAD.Pro V8i

Figure 4: Beam Hinge results for a Structure in STAAD.Pro V8i

STAAD Results

P R O B L E M S T A T I S T I C S

NUMBER OF JOINTS/MEMBER+ELEMENTS/SUPPORTS = 15/ 20/ 3

SOLVER USED IS THE IN-CORE ADVANCED SOLVER

TOTAL PRIMARY LOAD CASES = 1, TOTAL DEGREES OF FREEDOM = 36

NUMBER OF MODES REQUESTED = 1

NUMBER OF EXISTING MASSES IN THE MODEL = 24

NUMBER OF MODES THAT WILL BE USED = 1

STAAD PLANE -- PAGE NO. 3

CALCULATED FREQUENCIES FOR LOAD CASE 2

MODE FREQUENCY(CYCLES/SEC) PERIOD(SEC)

1 1.292 0.77396

MASS PARTICIPATION FACTORS IN PERCENT

MODE X Y Z SUMM-X SUMM-Y SUMM-Z

1 79.94 0.00 0.00 79.944 0.000 0.000

Tags: STAAD.Pro, TechNote, pushover analysis

Pushover Analysis of Steel Structure using STAAD (TN)

Steve Crabtree — Wed, 22 Jun 2016 17:13:57 GMT

Revision 5 posted to RAM | STAAD | ADINA Wiki by Steve Crabtree on 6/22/2016 5:13:57 PM


	Applies To

	Product(s):	STAAD.Pro
	Version(s):	All
	Environment:	N/A
	Area:	Pushover Analysis of Steel Structure using STAAD
	Subarea:	N/A
	Original Author:	Bentley Technical Support Group

Pushover Analysis

Steel Structure using STAAD

Bentley Systems

Mr. Kalavagunta Sreedhar)

Definition

Purpose of Pushover Analysis

Theory on which it is based

There are two nonlinear procedures using pushover methods:

a) Capacity Spectrum Method,

b) Displacement Coefficient Method.

In STAAD Displacement Coefficient method has been followed.

Types of non-linearity

Both geometric and material non-linearities are considered in this static nonlinear pushover analysis.

Geometric non-linearity

Material non-linearity

Frame element hinge properties

Discrete hinge properties for frame elements are based on FEMA-356 criteria as per Section 5.5.2.2.2.

Figure1.6 Generalized Force-Deformation Relationship for Components

Point A is the origin
Point B represents yielding. No deformation occurs in the hinge up to point B, regardless of the deformation value specified for point B. The displacement (rotation or axial elongation as the case may be) will be subtracted from the displacements at points C, D and E. Only plastic deformation beyond point B will be exhibited by hinge.
Point C represents ultimate capacity of plastic hinge. At this point hinge strength degradation begins (hinge starts shedding load) until it reaches point D.
Point D represents the residual strength of the plastic hinge. Beyond point D the component responds with substantially strength to point E.
Point E represnts total failure. At deformation greater than point E the plastic hinge will drop load to zero.

Lateral Load Distribution as per Section 3.3.3.2.3 Chapter 3 FEMA 356

Lateral load can be applied by following three methods.

Method 1

F_x = C_vxV …………………………. (1-8-1)

where

w_xh^k_x

C_vx = -------------------- …………………………. (1-8-2)

S w_ih^k_i

i = 1

Method 2

w_xF_x

F_x = --------------- V

S w_iF_i

ⁱ^{= 1}

Method 3

A vertical distribution is performed consisting of lateral forces at each level proportional to the total mass at each level .

w_x

F_x = --------- V

S w_i

ⁱ^{= 1}

where,

C_vx = Vertical distribution factor

k = 2.0 for T 2.5 seconds ≥

= 1.0 for T 0.5 seconds ≤

Linear interpolation shall be used to calculate values of for intermediate values of k for

intermediate values of T.

V = User defined base shear

w_i = Portion of the total building weight W located on or assigned to floor level i

w_x = Portion of the total building weight W located on or assigned to floor level x

h_i = Height (in ft) from the base to floor level i

h_x = Height (in ft) from the base to floor level x

F_x= Amplitude of mode a floor level x

Masses

The method involves 2 matrices – the stiffness matrix and the mass matrix.

Example.

Illustrate the procedure and results find the bellow STAAD example

STAAD PLANE

START JOB INFORMATION

ENGINEER DATE 07-Oct-05

END JOB INFORMATION

INPUT WIDTH 79

UNIT INCHES KIP

JOINT COORDINATES

1 0 0 0; 2 0 118.11 0; 3 118.11 118.11 0; 4 118.11 0 0; 5 0 236.22 0;

6 118.11 236.22 0; 7 0 354.331 0; 8 118.11 354.331 0; 9 0 472.441 0;

10 118.11 472.441 0; 11 236.22 118.11 0; 12 236.22 0 0; 13 236.22 236.22 0;

14 236.22 354.331 0; 15 236.22 472.441 0;

MEMBER INCIDENCES

1 1 2; 2 2 3; 3 3 4; 4 2 5; 5 5 6; 6 6 3; 7 5 7; 8 7 8; 9 8 6; 10 7 9; 11 9 10;

12 10 8; 13 3 11; 14 6 13; 15 8 14; 16 10 15; 17 11 12; 18 13 11; 19 14 13;

20 15 14;

DEFINE MATERIAL START

ISOTROPIC STEEL

E 29732.7

POISSON 0.3

DENSITY 0.000283

ALPHA 1.2e-005

DAMP 0.03

END DEFINE MATERIAL

MEMBER PROPERTY AMERICAN

2 5 13 14 TABLE ST W16X26

8 11 15 16 TABLE ST W16X26

1 3 4 6 17 18 TABLE ST W24X55

7 9 10 12 19 20 TABLE ST W24X55

CONSTANTS

MATERIAL STEEL ALL

SUPPORTS

1 4 12 FIXED

DEFINE PUSHOVER DATA

FRAME 2

FYE 36.000000 ALL

GNONL 1

DISP X 15 JOINT 10

LDSTEP 250

SPECTRUM PARAMETERS

DAMPING 5.0000

SC 1

SS 1

S1 1

SAVE LOADSTEP RESULT DISP 0.010000

END PUSHOVER DATA

LOAD 1 LOADTYPE Gravity

SELFWEIGHT Y -1

MEMBER LOAD

2 5 8 11 13 TO 16 UNI GY -.4

PERFORM PUSHOVER ANALYSIS

FINISH

Figure 1: Capacity Curve for a Structure in STAAD.Pro V8i

Figure 2: Deflected shape at specified displacement for a Structure in STAAD.Pro V8i

Figure 4: Beam Hinge results for a Structure in STAAD.Pro V8i

STAAD Results

P R O B L E M S T A T I S T I C S

NUMBER OF JOINTS/MEMBER+ELEMENTS/SUPPORTS = 15/ 20/ 3

SOLVER USED IS THE IN-CORE ADVANCED SOLVER

TOTAL PRIMARY LOAD CASES = 1, TOTAL DEGREES OF FREEDOM = 36

NUMBER OF MODES REQUESTED = 1

NUMBER OF EXISTING MASSES IN THE MODEL = 24

NUMBER OF MODES THAT WILL BE USED = 1

STAAD PLANE -- PAGE NO. 3

CALCULATED FREQUENCIES FOR LOAD CASE 2

MODE FREQUENCY(CYCLES/SEC) PERIOD(SEC)

1 1.292 0.77396

MASS PARTICIPATION FACTORS IN PERCENT

MODE X Y Z SUMM-X SUMM-Y SUMM-Z

1 79.94 0.00 0.00 79.944 0.000 0.000

Tags: STAAD.Pro, TechNote, pushover analysis

Pushover Analysis of Steel Structure using STAAD (TN)

Sye — Tue, 13 Aug 2013 23:34:08 GMT

Revision 4 posted to RAM | STAAD | ADINA Wiki by Sye on 8/13/2013 11:34:08 PM

Pushover Analysis

Steel Structure using STAAD

Bentley Systems

Mr. Kalavagunta Sreedhar)

Definition

Purpose of Pushover Analysis

Theory on which it is based

There are two nonlinear procedures using pushover methods:

a) Capacity Spectrum Method,

b) Displacement Coefficient Method.

In STAAD Displacement Coefficient method has been followed.

Types of non-linearity

Both geometric and material non-linearities are considered in this static nonlinear pushover analysis.

Geometric non-linearity

Material non-linearity

Frame element hinge properties

Discrete hinge properties for frame elements are based on FEMA-356 criteria as per Section 5.5.2.2.2.

Figure1.6 Generalized Force-Deformation Relationship for Components

Point A is the origin
Point B represents yielding. No deformation occurs in the hinge up to point B, regardless of the deformation value specified for point B. The displacement (rotation or axial elongation as the case may be) will be subtracted from the displacements at points C, D and E. Only plastic deformation beyond point B will be exhibited by hinge.
Point C represents ultimate capacity of plastic hinge. At this point hinge strength degradation begins (hinge starts shedding load) until it reaches point D.
Point D represents the residual strength of the plastic hinge. Beyond point D the component responds with substantially strength to point E.
Point E represnts total failure. At deformation greater than point E the plastic hinge will drop load to zero.

Lateral Load Distribution as per Section 3.3.3.2.3 Chapter 3 FEMA 356

Lateral load can be applied by following three methods.

Method 1

F_x = C_vxV …………………………. (1-8-1)

where

w_xh^k_x

C_vx = -------------------- …………………………. (1-8-2)

S w_ih^k_i

i = 1

Method 2

w_xF_x

F_x = --------------- V

S w_iF_i

ⁱ^{= 1}

Method 3

A vertical distribution is performed consisting of lateral forces at each level proportional to the total mass at each level .

w_x

F_x = --------- V

S w_i

ⁱ^{= 1}

where,

C_vx = Vertical distribution factor

k = 2.0 for T 2.5 seconds ≥

= 1.0 for T 0.5 seconds ≤

Linear interpolation shall be used to calculate values of for intermediate values of k for

intermediate values of T.

V = User defined base shear

w_i = Portion of the total building weight W located on or assigned to floor level i

w_x = Portion of the total building weight W located on or assigned to floor level x

h_i = Height (in ft) from the base to floor level i

h_x = Height (in ft) from the base to floor level x

F_x= Amplitude of mode a floor level x

Masses

The method involves 2 matrices – the stiffness matrix and the mass matrix.

Example.

Illustrate the procedure and results find the bellow STAAD example

STAAD PLANE

START JOB INFORMATION

ENGINEER DATE 07-Oct-05

END JOB INFORMATION

INPUT WIDTH 79

UNIT INCHES KIP

JOINT COORDINATES

1 0 0 0; 2 0 118.11 0; 3 118.11 118.11 0; 4 118.11 0 0; 5 0 236.22 0;

6 118.11 236.22 0; 7 0 354.331 0; 8 118.11 354.331 0; 9 0 472.441 0;

10 118.11 472.441 0; 11 236.22 118.11 0; 12 236.22 0 0; 13 236.22 236.22 0;

14 236.22 354.331 0; 15 236.22 472.441 0;

MEMBER INCIDENCES

1 1 2; 2 2 3; 3 3 4; 4 2 5; 5 5 6; 6 6 3; 7 5 7; 8 7 8; 9 8 6; 10 7 9; 11 9 10;

12 10 8; 13 3 11; 14 6 13; 15 8 14; 16 10 15; 17 11 12; 18 13 11; 19 14 13;

20 15 14;

DEFINE MATERIAL START

ISOTROPIC STEEL

E 29732.7

POISSON 0.3

DENSITY 0.000283

ALPHA 1.2e-005

DAMP 0.03

END DEFINE MATERIAL

MEMBER PROPERTY AMERICAN

2 5 13 14 TABLE ST W16X26

8 11 15 16 TABLE ST W16X26

1 3 4 6 17 18 TABLE ST W24X55

7 9 10 12 19 20 TABLE ST W24X55

CONSTANTS

MATERIAL STEEL ALL

SUPPORTS

1 4 12 FIXED

DEFINE PUSHOVER DATA

FRAME 2

FYE 36.000000 ALL

GNONL 1

DISP X 15 JOINT 10

LDSTEP 250

SPECTRUM PARAMETERS

DAMPING 5.0000

SC 1

SS 1

S1 1

SAVE LOADSTEP RESULT DISP 0.010000

END PUSHOVER DATA

LOAD 1 LOADTYPE Gravity

SELFWEIGHT Y -1

MEMBER LOAD

2 5 8 11 13 TO 16 UNI GY -.4

PERFORM PUSHOVER ANALYSIS

FINISH

Figure 1: Capacity Curve for a Structure in STAAD.Pro V8i

Figure 2: Deflected shape at specified displacement for a Structure in STAAD.Pro V8i

Figure 4: Beam Hinge results for a Structure in STAAD.Pro V8i

STAAD Results

P R O B L E M S T A T I S T I C S

NUMBER OF JOINTS/MEMBER+ELEMENTS/SUPPORTS = 15/ 20/ 3

SOLVER USED IS THE IN-CORE ADVANCED SOLVER

TOTAL PRIMARY LOAD CASES = 1, TOTAL DEGREES OF FREEDOM = 36

NUMBER OF MODES REQUESTED = 1

NUMBER OF EXISTING MASSES IN THE MODEL = 24

NUMBER OF MODES THAT WILL BE USED = 1

STAAD PLANE -- PAGE NO. 3

CALCULATED FREQUENCIES FOR LOAD CASE 2

MODE FREQUENCY(CYCLES/SEC) PERIOD(SEC)

1 1.292 0.77396

MASS PARTICIPATION FACTORS IN PERCENT

MODE X Y Z SUMM-X SUMM-Y SUMM-Z

1 79.94 0.00 0.00 79.944 0.000 0.000

Tags: STAAD.Pro, TechNote, pushover analysis

Pushover Analysis of Steel Structure using STAAD

Jeremy Hoesly — Wed, 28 Jul 2010 23:35:51 GMT

Revision 3 posted to RAM | STAAD | ADINA Wiki by Jeremy Hoesly on 7/28/2010 11:35:51 PM

Pushover Analysis

Steel Structure using STAAD

Bentley Systems

Mr. Kalavagunta Sreedhar)

Definition

Purpose of Pushover Analysis

Theory on which it is based

There are two nonlinear procedures using pushover methods:

a) Capacity Spectrum Method,

b) Displacement Coefficient Method.

In STAAD Displacement Coefficient method has been followed.

Types of non-linearity

Both geometric and material non-linearities are considered in this static nonlinear pushover analysis.

Geometric non-linearity

Material non-linearity

Frame element hinge properties

Discrete hinge properties for frame elements are based on FEMA-356 criteria as per Section 5.5.2.2.2.

Figure1.6 Generalized Force-Deformation Relationship for Components

Point A is the origin
Point B represents yielding. No deformation occurs in the hinge up to point B, regardless of the deformation value specified for point B. The displacement (rotation or axial elongation as the case may be) will be subtracted from the displacements at points C, D and E. Only plastic deformation beyond point B will be exhibited by hinge.
Point C represents ultimate capacity of plastic hinge. At this point hinge strength degradation begins (hinge starts shedding load) until it reaches point D.
Point D represents the residual strength of the plastic hinge. Beyond point D the component responds with substantially strength to point E.
Point E represnts total failure. At deformation greater than point E the plastic hinge will drop load to zero.

Lateral Load Distribution as per Section 3.3.3.2.3 Chapter 3 FEMA 356

Lateral load can be applied by following three methods.

Method 1

F_x = C_vxV …………………………. (1-8-1)

where

w_xh^k_x

C_vx = -------------------- …………………………. (1-8-2)

S w_ih^k_i

i = 1

Method 2

w_xF_x

F_x = --------------- V

S w_iF_i

ⁱ^{= 1}

Method 3

A vertical distribution is performed consisting of lateral forces at each level proportional to the total mass at each level .

w_x

F_x = --------- V

S w_i

ⁱ^{= 1}

where,

C_vx = Vertical distribution factor

k = 2.0 for T 2.5 seconds ≥

= 1.0 for T 0.5 seconds ≤

Linear interpolation shall be used to calculate values of for intermediate values of k for

intermediate values of T.

V = User defined base shear

w_i = Portion of the total building weight W located on or assigned to floor level i

w_x = Portion of the total building weight W located on or assigned to floor level x

h_i = Height (in ft) from the base to floor level i

h_x = Height (in ft) from the base to floor level x

F_x= Amplitude of mode a floor level x

Masses

The method involves 2 matrices – the stiffness matrix and the mass matrix.

Example.

Illustrate the procedure and results find the bellow STAAD example

STAAD PLANE

START JOB INFORMATION

ENGINEER DATE 07-Oct-05

END JOB INFORMATION

INPUT WIDTH 79

UNIT INCHES KIP

JOINT COORDINATES

1 0 0 0; 2 0 118.11 0; 3 118.11 118.11 0; 4 118.11 0 0; 5 0 236.22 0;

6 118.11 236.22 0; 7 0 354.331 0; 8 118.11 354.331 0; 9 0 472.441 0;

10 118.11 472.441 0; 11 236.22 118.11 0; 12 236.22 0 0; 13 236.22 236.22 0;

14 236.22 354.331 0; 15 236.22 472.441 0;

MEMBER INCIDENCES

1 1 2; 2 2 3; 3 3 4; 4 2 5; 5 5 6; 6 6 3; 7 5 7; 8 7 8; 9 8 6; 10 7 9; 11 9 10;

12 10 8; 13 3 11; 14 6 13; 15 8 14; 16 10 15; 17 11 12; 18 13 11; 19 14 13;

20 15 14;

DEFINE MATERIAL START

ISOTROPIC STEEL

E 29732.7

POISSON 0.3

DENSITY 0.000283

ALPHA 1.2e-005

DAMP 0.03

END DEFINE MATERIAL

MEMBER PROPERTY AMERICAN

2 5 13 14 TABLE ST W16X26

8 11 15 16 TABLE ST W16X26

1 3 4 6 17 18 TABLE ST W24X55

7 9 10 12 19 20 TABLE ST W24X55

CONSTANTS

MATERIAL STEEL ALL

SUPPORTS

1 4 12 FIXED

DEFINE PUSHOVER DATA

FRAME 2

FYE 36.000000 ALL

GNONL 1

DISP X 15 JOINT 10

LDSTEP 250

SPECTRUM PARAMETERS

DAMPING 5.0000

SC 1

SS 1

S1 1

SAVE LOADSTEP RESULT DISP 0.010000

END PUSHOVER DATA

LOAD 1 LOADTYPE Gravity

SELFWEIGHT Y -1

MEMBER LOAD

2 5 8 11 13 TO 16 UNI GY -.4

PERFORM PUSHOVER ANALYSIS

FINISH

Figure 1: Capacity Curve for a Structure in STAAD.Pro V8i

Figure 2: Deflected shape at specified displacement for a Structure in STAAD.Pro V8i

Figure 4: Beam Hinge results for a Structure in STAAD.Pro V8i

STAAD Results

P R O B L E M S T A T I S T I C S

NUMBER OF JOINTS/MEMBER+ELEMENTS/SUPPORTS = 15/ 20/ 3

SOLVER USED IS THE IN-CORE ADVANCED SOLVER

TOTAL PRIMARY LOAD CASES = 1, TOTAL DEGREES OF FREEDOM = 36

NUMBER OF MODES REQUESTED = 1

NUMBER OF EXISTING MASSES IN THE MODEL = 24

NUMBER OF MODES THAT WILL BE USED = 1

STAAD PLANE -- PAGE NO. 3

CALCULATED FREQUENCIES FOR LOAD CASE 2

MODE FREQUENCY(CYCLES/SEC) PERIOD(SEC)

1 1.292 0.77396

MASS PARTICIPATION FACTORS IN PERCENT

MODE X Y Z SUMM-X SUMM-Y SUMM-Z

1 79.94 0.00 0.00 79.944 0.000 0.000

Tags: TechNote, STAAD.Pro

Pushover Analysis of Steel Structure using STAAD

Sreedhar Kalavagunta — Thu, 17 Jun 2010 08:20:22 GMT

Revision 2 posted to RAM | STAAD | ADINA Wiki by Sreedhar Kalavagunta on 6/17/2010 8:20:22 AM

Pushover Analysis

Steel Structure using STAAD

Bentley Systems

Mr. Kalavagunta Sreedhar)

Definition

Purpose of Pushover Analysis

Theory on which it is based

There are two nonlinear procedures using pushover methods:

a) Capacity Spectrum Method,

b) Displacement Coefficient Method.

In STAAD Displacement Coefficient method has been followed.

Types of non-linearity

Both geometric and material non-linearities are considered in this static nonlinear pushover analysis.

Geometric non-linearity

Material non-linearity

Frame element hinge properties

Discrete hinge properties for frame elements are based on FEMA-356 criteria as per Section 5.5.2.2.2.

Figure1.6 Generalized Force-Deformation Relationship for Components

Point A is the origin
Point B represents yielding. No deformation occurs in the hinge up to point B, regardless of the deformation value specified for point B. The displacement (rotation or axial elongation as the case may be) will be subtracted from the displacements at points C, D and E. Only plastic deformation beyond point B will be exhibited by hinge.
Point C represents ultimate capacity of plastic hinge. At this point hinge strength degradation begins (hinge starts shedding load) until it reaches point D.
Point D represents the residual strength of the plastic hinge. Beyond point D the component responds with substantially strength to point E.
Point E represnts total failure. At deformation greater than point E the plastic hinge will drop load to zero.

Lateral Load Distribution as per Section 3.3.3.2.3 Chapter 3 FEMA 356

Lateral load can be applied by following three methods.

Method 1

F_x = C_vxV …………………………. (1-8-1)

where

w_xh^k_x

C_vx = -------------------- …………………………. (1-8-2)

S w_ih^k_i

i = 1

Method 2

w_xF_x

F_x = --------------- V

S w_iF_i

ⁱ^{= 1}

Method 3

A vertical distribution is performed consisting of lateral forces at each level proportional to the total mass at each level .

w_x

F_x = --------- V

S w_i

ⁱ^{= 1}

where,

C_vx = Vertical distribution factor

k = 2.0 for T 2.5 seconds ≥

= 1.0 for T 0.5 seconds ≤

Linear interpolation shall be used to calculate values of for intermediate values of k for

intermediate values of T.

V = User defined base shear

w_i = Portion of the total building weight W located on or assigned to floor level i

w_x = Portion of the total building weight W located on or assigned to floor level x

h_i = Height (in ft) from the base to floor level i

h_x = Height (in ft) from the base to floor level x

F_x= Amplitude of mode a floor level x

Masses

The method involves 2 matrices – the stiffness matrix and the mass matrix.

Example.

Illustrate the procedure and results find the bellow STAAD example

STAAD PLANE

START JOB INFORMATION

ENGINEER DATE 07-Oct-05

END JOB INFORMATION

INPUT WIDTH 79

UNIT INCHES KIP

JOINT COORDINATES

1 0 0 0; 2 0 118.11 0; 3 118.11 118.11 0; 4 118.11 0 0; 5 0 236.22 0;

6 118.11 236.22 0; 7 0 354.331 0; 8 118.11 354.331 0; 9 0 472.441 0;

10 118.11 472.441 0; 11 236.22 118.11 0; 12 236.22 0 0; 13 236.22 236.22 0;

14 236.22 354.331 0; 15 236.22 472.441 0;

MEMBER INCIDENCES

1 1 2; 2 2 3; 3 3 4; 4 2 5; 5 5 6; 6 6 3; 7 5 7; 8 7 8; 9 8 6; 10 7 9; 11 9 10;

12 10 8; 13 3 11; 14 6 13; 15 8 14; 16 10 15; 17 11 12; 18 13 11; 19 14 13;

20 15 14;

DEFINE MATERIAL START

ISOTROPIC STEEL

E 29732.7

POISSON 0.3

DENSITY 0.000283

ALPHA 1.2e-005

DAMP 0.03

END DEFINE MATERIAL

MEMBER PROPERTY AMERICAN

2 5 13 14 TABLE ST W16X26

8 11 15 16 TABLE ST W16X26

1 3 4 6 17 18 TABLE ST W24X55

7 9 10 12 19 20 TABLE ST W24X55

CONSTANTS

MATERIAL STEEL ALL

SUPPORTS

1 4 12 FIXED

DEFINE PUSHOVER DATA

FRAME 2

FYE 36.000000 ALL

GNONL 1

DISP X 15 JOINT 10

LDSTEP 250

SPECTRUM PARAMETERS

DAMPING 5.0000

SC 1

SS 1

S1 1

SAVE LOADSTEP RESULT DISP 0.010000

END PUSHOVER DATA

LOAD 1 LOADTYPE Gravity

SELFWEIGHT Y -1

MEMBER LOAD

2 5 8 11 13 TO 16 UNI GY -.4

PERFORM PUSHOVER ANALYSIS

FINISH

Figure 1: Capacity Curve for a Structure in STAAD.Pro V8i

Figure 2: Deflected shape at specified displacement for a Structure in STAAD.Pro V8i

Figure 4: Beam Hinge results for a Structure in STAAD.Pro V8i

STAAD Results

P R O B L E M S T A T I S T I C S

NUMBER OF JOINTS/MEMBER+ELEMENTS/SUPPORTS = 15/ 20/ 3

SOLVER USED IS THE IN-CORE ADVANCED SOLVER

TOTAL PRIMARY LOAD CASES = 1, TOTAL DEGREES OF FREEDOM = 36

NUMBER OF MODES REQUESTED = 1

NUMBER OF EXISTING MASSES IN THE MODEL = 24

NUMBER OF MODES THAT WILL BE USED = 1

STAAD PLANE -- PAGE NO. 3

CALCULATED FREQUENCIES FOR LOAD CASE 2

MODE FREQUENCY(CYCLES/SEC) PERIOD(SEC)

1 1.292 0.77396

MASS PARTICIPATION FACTORS IN PERCENT

MODE X Y Z SUMM-X SUMM-Y SUMM-Z

1 79.94 0.00 0.00 79.944 0.000 0.000

Pushover Analysis of Steel Structure using STAAD

Sreedhar Kalavagunta — Thu, 17 Jun 2010 08:17:59 GMT

Revision 1 posted to RAM | STAAD | ADINA Wiki by Sreedhar Kalavagunta on 6/17/2010 8:17:59 AM

Pushover Analysis

Steel Structure using STAAD

Bentley Systems

Mr. Kalavagunta Sreedhar)

Definition

Purpose of Pushover Analysis

Theory on which it is based

There are two nonlinear procedures using pushover methods:

a) Capacity Spectrum Method,

b) Displacement Coefficient Method.

In STAAD Displacement Coefficient method has been followed.

Types of non-linearity

Both geometric and material non-linearities are considered in this static nonlinear pushover analysis.

Geometric non-linearity

Material non-linearity

Frame element hinge properties

Discrete hinge properties for frame elements are based on FEMA-356 criteria as per Section 5.5.2.2.2.

Figure1.6 Generalized Force-Deformation Relationship for Components

Point A is the origin
Point B represents yielding. No deformation occurs in the hinge up to point B, regardless of the deformation value specified for point B. The displacement (rotation or axial elongation as the case may be) will be subtracted from the displacements at points C, D and E. Only plastic deformation beyond point B will be exhibited by hinge.
Point C represents ultimate capacity of plastic hinge. At this point hinge strength degradation begins (hinge starts shedding load) until it reaches point D.
Point D represents the residual strength of the plastic hinge. Beyond point D the component responds with substantially strength to point E.
Point E represnts total failure. At deformation greater than point E the plastic hinge will drop load to zero.

Lateral Load Distribution as per Section 3.3.3.2.3 Chapter 3 FEMA 356

Lateral load can be applied by following three methods.

Method 1

F_x = C_vxV …………………………. (1-8-1)

where

w_xh^k_x

C_vx = -------------------- …………………………. (1-8-2)

S w_ih^k_i

i = 1

Method 2

w_xF_x

F_x = --------------- V

S w_iF_i

ⁱ^{= 1}

Method 3

A vertical distribution is performed consisting of lateral forces at each level proportional to the total mass at each level .

w_x

F_x = --------- V

S w_i

ⁱ^{= 1}

where,

C_vx = Vertical distribution factor

k = 2.0 for T 2.5 seconds ≥

= 1.0 for T 0.5 seconds ≤

Linear interpolation shall be used to calculate values of for intermediate values of k for

intermediate values of T.

V = User defined base shear

w_i = Portion of the total building weight W located on or assigned to floor level i

w_x = Portion of the total building weight W located on or assigned to floor level x

h_i = Height (in ft) from the base to floor level i

h_x = Height (in ft) from the base to floor level x

F_x= Amplitude of mode a floor level x

Masses

The method involves 2 matrices – the stiffness matrix and the mass matrix.

Example.

Illustrate the procedure and results find the bellow STAAD example

STAAD PLANE

START JOB INFORMATION

ENGINEER DATE 07-Oct-05

END JOB INFORMATION

INPUT WIDTH 79

UNIT INCHES KIP

JOINT COORDINATES

1 0 0 0; 2 0 118.11 0; 3 118.11 118.11 0; 4 118.11 0 0; 5 0 236.22 0;

6 118.11 236.22 0; 7 0 354.331 0; 8 118.11 354.331 0; 9 0 472.441 0;

10 118.11 472.441 0; 11 236.22 118.11 0; 12 236.22 0 0; 13 236.22 236.22 0;

14 236.22 354.331 0; 15 236.22 472.441 0;

MEMBER INCIDENCES

1 1 2; 2 2 3; 3 3 4; 4 2 5; 5 5 6; 6 6 3; 7 5 7; 8 7 8; 9 8 6; 10 7 9; 11 9 10;

12 10 8; 13 3 11; 14 6 13; 15 8 14; 16 10 15; 17 11 12; 18 13 11; 19 14 13;

20 15 14;

DEFINE MATERIAL START

ISOTROPIC STEEL

E 29732.7

POISSON 0.3

DENSITY 0.000283

ALPHA 1.2e-005

DAMP 0.03

END DEFINE MATERIAL

MEMBER PROPERTY AMERICAN

2 5 13 14 TABLE ST W16X26

8 11 15 16 TABLE ST W16X26

1 3 4 6 17 18 TABLE ST W24X55

7 9 10 12 19 20 TABLE ST W24X55

CONSTANTS

MATERIAL STEEL ALL

SUPPORTS

1 4 12 FIXED

DEFINE PUSHOVER DATA

FRAME 2

FYE 36.000000 ALL

GNONL 1

DISP X 15 JOINT 10

LDSTEP 250

SPECTRUM PARAMETERS

DAMPING 5.0000

SC 1

SS 1

S1 1

SAVE LOADSTEP RESULT DISP 0.010000

END PUSHOVER DATA

LOAD 1 LOADTYPE Gravity

SELFWEIGHT Y -1

MEMBER LOAD

2 5 8 11 13 TO 16 UNI GY -.4

PERFORM PUSHOVER ANALYSIS

FINISH

Figure 1: Capacity Curve for a Structure in STAAD.Pro V8i

Figure 2: Deflected shape at specified displacement for a Structure in STAAD.Pro V8i

Figure 4: Beam Hinge results for a Structure in STAAD.Pro V8i

STAAD Results

P R O B L E M S T A T I S T I C S

NUMBER OF JOINTS/MEMBER+ELEMENTS/SUPPORTS = 15/ 20/ 3

SOLVER USED IS THE IN-CORE ADVANCED SOLVER

TOTAL PRIMARY LOAD CASES = 1, TOTAL DEGREES OF FREEDOM = 36

NUMBER OF MODES REQUESTED = 1

NUMBER OF EXISTING MASSES IN THE MODEL = 24

NUMBER OF MODES THAT WILL BE USED = 1

STAAD PLANE -- PAGE NO. 3

CALCULATED FREQUENCIES FOR LOAD CASE 2

MODE FREQUENCY(CYCLES/SEC) PERIOD(SEC)

1 1.292 0.77396

MASS PARTICIPATION FACTORS IN PERCENT

MODE X Y Z SUMM-X SUMM-Y SUMM-Z

1 79.94 0.00 0.00 79.944 0.000 0.000