Hi guys, I am trying to work with Bentley PowerCivil for a university project. I need to extract in dwg from my model the vertical profile of the track and the vertical profile of the terrain model. I tried to export in dwg from File -> Export -> DGN,DWG,DXF but I obtain only the x,y view (planimetry) or the 3d model. How can I export to dwg the profiles I need? I didn't find any information on this in the forum.
Thank you very much
Try to create and export profiles using native.
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Hi Andrea
You may wish to consider exporting to LandXML format. Refer to http://www.landxml.org/
Find attached sample file which can be open with Notepad
jan96down.xml
Horizontal alignment is denoted by <CoordGeom>
<Alignment name="jan96down" length="110214.776597" staStart="0.000035" desc="ctrl down line, alp 18/7/96" state="proposed"> <CoordGeom name="jan96down" desc="ctrl down line, alp 18/7/96" state="proposed"> <Line length="532.195261" dir="5.804448132" staStart="0.000035"> <Start code="POB"> 62969.158200 10134.120310 0.000000 </Start> <End code="PC"> 63441.522666 9888.959939 0.000000 </End> <Feature code="Line"> <Property label="style" value="Default"/> </Feature> </Line> <Curve rot="cw" length="129.706120" chord="128.882806" dirStart="5.804448132" dirEnd="6.195129216" staStart="532.195296" radius="332.000000"> <Start code="PC"> 63441.522666 9888.959939 0.000000 </Start> <Center code="CC"> 63594.461351 10183.635623 0.000000 </Center> <End code="CS"> 63565.264494 9852.921935 0.000000 </End>
.............
<Curve rot="cw" length="179.053272" chord="179.026697" dirStart="1.297270304" dirEnd="1.356954728" staStart="109714.856279" radius="3000.000000"> <Start code="SC"> 17434.075767 99213.926063 0.000000 </Start> <Center code="CC"> 14545.602549 100024.310211 0.000000 </Center> <End code="CS"> 17477.271191 99387.663547 0.000000 </End> <Feature code="Curve"> <Property label="style" value="Default"/> </Feature> </Curve> <Spiral length="80.000000" radiusEnd="INF" radiusStart="3000.000000" rot="cw" spiType="clothoid" dirStart="1.356954728" dirEnd="1.370288062" staStart="109893.909551" constant="489.897949" theta="0.013333333" totalY="0.355551" totalX="79.998578" tanLong="53.333830" tanShort="26.667118"> <Start code="CS"> 17477.271191 99387.663547 0.000000 </Start> <PI code="PI"> 17482.930368 99413.723266 0.000000 </PI> <End code="ST"> 17493.552731 99465.988578 0.000000 </End> <Feature code="Spiral"> <Property label="style" value="Default"/> </Feature> </Spiral> <Line length="240.867080" dir="1.370288062" staStart="109973.909551"> <Start code="ST"> 17493.552731 99465.988578 0.000000 </Start> <End code="POE"> 17541.525610 99702.030000 0.000000 </End> <Feature code="Line"> <Property label="style" value="Default"/> </Feature> </Line> </CoordGeom>
</CoordGeom>
Vertical alignment is denoted by <Profile>. For example,
<ProfAlign name="down" desc="down line VAlg 20.6.96"> <PVI> 0.000000 21.519000 </PVI> <ParaCurve length="25.411274"> 427.704000 22.792000 </ParaCurve> <ParaCurve length="81.165628"> STA Elevation </ParaCurve>
<ParaCurve length="118.518387"> 109280.698000 66.620600 </ParaCurve> <PVI> 110214.777000 56.888080 </PVI>
Regards
Gary
Answer Verified By: Andrea Bernardini
Thank you very much!