Left and right side of Template Drop not ending on the same chainage (no squared)

Question

I have a corridor (in OpenRoads) with various template drops. I have one template drop going across a bridge, but the left side and right side are starting and ending on different chainages (not squared off). I have tried to split my template drop into 2 template drops. one LHS the other RHS so I can start and end at different chainages. When I add the LHS template drop it comes in, then when I add the second Template drop (RHS) the RHS appears but the start and end of the LHS disappear. I can add them both in separately but cannot have them in together. I am using the Road Centreline as referend. I then have the same issue on either side of the bridge that join these. LHS will join, as will the RHS but not together. 
 I have tried 2 corridors and clip but that didn't work (even though it worked on another model for another modeller). 
 To summarise using simple chainages as an example - Left Hand Side of the road - Template Drop A = Chainage starts at 100 ends in 175 then going over the bridge ( Template Drop B) starts at 175 ends in 275 and then goes back to Template Drop A . 
 Right Hand Side of the Road - Template Drop C - Chainage starts at 100 ends in 165 then going over the bridge (Template Drop D) starts at 165 enf in 265 and then goes back to Template Drop C . 
 
 How can this be done in OpenRoads if my template drop is not square at the end as My barriers must tie into Parapets also, is there some setting I am missing or have I the wrong approach in modelling it ? 
 
 Thank you 
 Martin

Chris Andrew · Accepted Answer

I would use one template drop for both sides of your carriageway all the way across the bridge. 
 In the template include a matchline L and a matchline r null points. Set at 1m horizontal offset from the CL. Add a label to each one. Say "matchline L" & "matchlineR. 
 Then click on the first component you don't want to be displayed over the bridge and edit it. Setting up a new display rule to say if horizontal difference between matchlineL and CL is greater than 1m = false. So component is only displayed when parametric label is 1m or less. 
 You then need to parent any subsequent components to the first. For example. If the first was a shoulder then subsequent components might be daylight(gradings). 
 You can then replicate this for the Right side. And then add separate parametric constraints to the corridor. For example: MatchlineL -2m to -2m between 175 and 275 and MatchlineR 2m to 2m between 165 and 265. 
 The same approach can be used for pavement depth to reduce layer thickness or remove pavement layers over the bridge if needed.