I need to create a surface model of a stretch of roadway with two roundabouts. And I do not have a Roundabout add-in or extension for InRoads. I found the following post on this in the old discussion groups, saying it can be done and with some quick words of advice.
http://discussion.bentley.com/cgi-bin/dnewsweb.exe?cmd=article&group=bentley.inroads&item=13848&utag=
Can someone expand on how best to proceed with modeling such a roundabout, or direct me to a resource that would help?
Thanks,
Brian
InRoads 08.09.02.16
Microstation 08.05.02.35
Hi Brian,
I have modeled a couple of roundabout projects with this workflow:
First I create a vertical alignment for the roads passing thru the roundabout.
Then I model them with a simple template (just a 2% slope from the center without bothering to have any end conditions) that is wide enough to overlap the entire circle, I then generate an alignment for the lip of curb for each quadrant with the surface that was generated with the wide template visualized on it. I then design a vertical profile using that surface as a guide, and then I create a template from the curb out and model that to the existing ground.
I then visualize the top surface features of the curb, sidewalk, slope intersections etc. as well as the centerline of the roads and then import those graphics as a DTM. To get the splitter islands I drape the design surface at the face of the curb and a line slightly offset for the top of the curb and then move the graphics of the top vertically with a dx=0,0,.5 command
The one problem using this method is the pavement area is a simple surface, not a component so subgrade volumes cant be computed as normal.
Dwight
hi,
The post from old discussion groups you brought up, was orginaly posted by Piotr. He explored his post in BeGeneral PL Community Forum (search for the topic: '[IR]Projektowanie rond'). This forum requires authorization and it's in Polish, however some usefull drafts are atached.
Adam.
Best,
Adam
OpenRoads Designer 2022 (10.12) | OpenRail Designer 2022 (10.12)