Underground RCC tank

Hi all,

i have to design an underground RCC 4 chamber tank, for that i have modelled it with plates = 350mm as per IS 3370.

I was comparing the results of manual calculations with staad. they are not maching.

Staad shows maximum moment at the centre (two way bulging, thats ok because the ratio = 1), but the moment works out to be maximum of 17Kn.m as per staad while it comes out about 37Kn.m manually.

Second thing i also want to know whether the suppoerts modelled are correct, as the soil is silty sand with SBC  = 150 Kn/m2.

Please suggest necessay corrections, technically as well as in modeeling.

Thanks in advance. 

brine tanks.std
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  • Hi , I think that 15000 could be wright, this constant depends also on the geometry and dimension of the fundation, I dont Know If you use the expresion K BxB = K0,3 ((B + 0.3)/(2B))2 ;(Terzaghi, the expresion for square foundation in metric units)  where B is the distance between the walls,  (B = 4.85 m in your case) and K0,3 is the is the value of the modulus of the soil that you obtain by field test using a 0.30 x0.30 m plate .  Finally KBXL = KBxB (1 + 0.5 B/L )/1.5 where L is the lenght of the foundation ( L = 19.40 m in your case).

    Another thing is that the number of plates to represent the behavior of the fundation is very low, ( you have 5 x 5 plates) you need at least 8 x 8 plates in each tank. a quik correction will be divide each plate in four.

    I hope this help you

    Regards

    Atilio

Reply
  • Hi , I think that 15000 could be wright, this constant depends also on the geometry and dimension of the fundation, I dont Know If you use the expresion K BxB = K0,3 ((B + 0.3)/(2B))2 ;(Terzaghi, the expresion for square foundation in metric units)  where B is the distance between the walls,  (B = 4.85 m in your case) and K0,3 is the is the value of the modulus of the soil that you obtain by field test using a 0.30 x0.30 m plate .  Finally KBXL = KBxB (1 + 0.5 B/L )/1.5 where L is the lenght of the foundation ( L = 19.40 m in your case).

    Another thing is that the number of plates to represent the behavior of the fundation is very low, ( you have 5 x 5 plates) you need at least 8 x 8 plates in each tank. a quik correction will be divide each plate in four.

    I hope this help you

    Regards

    Atilio

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